Question

A sample of neon is collected at 2.7 atm and 12.0 oC. It has a volume of 2.25 L. What would be the volume of this gas at STP?

Answer 1

Answer:

5.82 L

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,  

V₁ = 2.25 L

V₂ = ?

P₁ = 2.7 atm

T₁ = 12 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (12 + 273.15) K = 285.15 K  

At STP, Pressure = 1 atm and Temperature = 273.15 K

So,

P₂ = 1 atm

T₂ = 273.15 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{2.7}\times {2.25}}{285.15}=\frac {{1}\times {V_2}}{273.15}$

Solving for V₂ , we get:

V₂ = 5.82 L