The presence of an atmosphere, temperature, and distance from the Sun do not affect a planet's gravity. Are the objects in the solar system still or are they in motion? The Sun's gravity pulls the planets in orbit around it, and some planets pull moons in orbit around them.
Answer:
pH of soltion will be 5.69
Explanation:
The pH of the solution will be due to excessive acid left and the salt formed. Thus, it will form a buffer solution.
The pH of buffer solution is calculated from Henderson Hassalbalch's equation, which is:
![pH=pKa+log(\frac{[salt]}{[acid]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%20%29)
The moles of acid taken :
The moles of base taken:
The moles of acid left after reaction :
The moles of salt formed = 4.5mmol
Putting values in equation
![pH=pKa+log(\frac{[salt]}{[acid]} )=4.74+log(\frac{4.5}{0.5})=5.69](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%20%29%3D4.74%2Blog%28%5Cfrac%7B4.5%7D%7B0.5%7D%29%3D5.69)
Excess reactant : Na
NaCl produced : = 16.497 g
<h3>Further explanation</h3>
Given
Reaction(balanced)
2Na + Cl₂⇒ 2NaCl
20 g Na
10 g Cl₂
Required
Excess reactant
NaCl produced
Solution
mol Na(Ar = 23 g/mol) :
= 20 : 23 = 0.87
mol Cl₂(MW=71 g/mol):
= 10 : 71 g/mol = 0.141
mol : coefficient :
Na = 0.87 : 2 = 0.435
Cl₂ = 0.141 : 1 = 0.141
Limiting reactant : Cl₂(smaller ratio)
Excess reactant : Na
Mol NaCl based on mol Cl₂, so mol NaCl :
= 2/1 x mol Cl₂
= 2/1 x 0.141
= 0.282
Mass NaCl :
= 0.282 x 58.5 g/mol
= 16.497 g
Answer:
<h2>1.2 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 30 g
volume= 25 mL
We have
We have the final answer as
<h3>1.2 g/mL</h3>
Hope this helps you
Answer:
3.37kg of NaCl is the salt content of the dead sea
Explanation:
A concentration of 33.7% means there are 33.7g of NaCl in 100mL of solution.
To solve this question we need to convert 10.0L to mililiters, and then, solve for the mass of NaCl in grams and convert it to kg:
<em>Volume in milliliters:</em>
10.0L * (1000mL / 1L) = 10000mL
<em>Mass of NaCl:</em>
10000mL * (33.7g NaCl / 100mL) = 3370g NaCl
<em>In kg:</em>
3370g * (1kg / 1000g) =
<h3>3.37kg of NaCl is the salt content of the dead sea</h3>
