Answer:
Xe will have the highest partial pressure
Explanation:
Using Dalton's law of partial pressures for ideal gases
p=P*x
where
p= partial pressure , P= total pressure and x = mole fraction = n / ∑n
since the number of moles is related with mass through
n= m/M
where
m= mass and M= molecular weight
then if m is the same for all the gases
x = m*M/ ∑ (m*M) = m*M/ m∑ M = M/∑ M
thus
p=P*x = P*M/ ∑ M
for the 3 gases
p₁=P*x₁ = P*M₁/ (M₁+M₂+M₃)
p₂=P*x₃ = P*M₂/ (M₁+M₂+M₃)
p₂=P*x₃ = P*M₃/ (M₁+M₂+M₃)
then for gasses under the same pressure (P=constant) and same mass (m=constant) , p is higher when the molecular weight is higher . Therefore Xe will have the highest partial pressure
Answer:
In the attached photo.
Explanation:
Hello,
You could find the structure in the attached photo, taking into account that the initial (Z) resembles to the trans arrangement for this alkene.
Best regards.
Answer:
THE PRESSURE EXERTED BY THE GAS IS THEREFORE 2.88 atm.
Explanation:
Boyle's law states that at constant temperature, the volume of a given mass of gas is inversely proportional to the pressure of the gas.
Mathematically, P1 V1 = P2 V2
Write out the values of the variables given:
P1 = 2.4 atm
V1 = 1.8 L
V2 = 1.5 L
P2 = unknown
Re-arranging the variables by making P2 the subject of the equation, we have:
P2 = P1 V1 / V2
P2 = 2.4 * 1.8 / 1.5
P2 = 2.9=88 atm
Hence, the pressure exerted by the gas is therefore 2.88 atm
Answer:
Multiply 3 by Avogadro's number.
Explanation:
The mole can be defined as the amount of a substance that contains Avogadro’s number of particles, 6.02 x 10²³.
For elementary particles:
Number of particles=
number of moles x 6.02 x10²³
From the question,
Number of moles = 3moles
Number of particles = 3 x 6.02 x10²³
<h3>
Answer:</h3>
The root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.
<h3>
Solution and Explanation:</h3>
- To find how fast molecules or particles of gases move at a particular temperature, the root mean square speed is calculated.
- Root mean square speed of a gas is calculated by using the formula;
Where R is the molar gas constant, T is the temperature and M is the molar mass of gas in Kg.
<h3>Step 1: Root mean square speed from O₂</h3>
Molar mass of Oxygen is 32.0 g/mol or 0.032 kg/mol
Temperature = 65 degrees Celsius or 338 K
Molar gas constant = 8.3145 J/k.mol
<h3>
Step 2: Root mean square speed of UF₆ </h3>
The molar mass of UF₆ is 352 g/mol or 0.352 kg/mol
Therefore; the root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.
