Which of the following is NOT a reason why chemical bonds are important? *

Chemistry

1 answer:

KengaRu [80]3 years ago

3 0

Answer:

the answer would be B :)

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When an aqueous solution of strontium chloride is added to an aqueous solution of potassium sulfate, a precipitation reaction oc

Georgia [21]

Answer:

$2Cl^{-}_{(aq)} + 2K^{-} _{(aq)} = 2KClx_{(aq)}$

Explanation:

The reaction is a precipitation reaction. In other words, the two aqueous solutions react to give the solid salt, potassium chloride (KCl) in this case.

$SrCl_{2} _{(aq)} + K_{2}SO_{4} _{(s)} = SrSO_{4} _{(aq)} + 2KCl_{(s)}$

Because the reaction product is a solid, the net ionic equation can be written as:

$2Cl^{-}_{(aq)} + 2K^{-} _{(aq)} = 2KClx_{(aq)}$

This is the resultant equation after removing spectator ions: sulfate and strontium.

3 0

2 years ago

24 POINTS!!!!!!!

solong [7]

C. An ionic bond is a bond between charged atoms while a covalent bond is a bond between opposite charges

5 0

2 years ago

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For the skeletal chemical equation BF3(g) + NaH(s) → B2H6(g) + NaF(s) what is the coefficient of B2H6 in the balanced equation?

KonstantinChe [14]

Answer:

Coefficient in front of the $B_2H_6$ in the balanced equation - 1

Explanation:

The unbalanced Chemical equation is shown below as:-

$BF_3+NaH\rightarrow B_2H_6+NaF$

On the left hand side,

There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.

On the right hand side,

There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.

Thus,

leftside, $BF_3$ must be multiplied by 2 to balance boron and right side, $NaF$ must be multiplied by 6 to balance fluorine. Left side, $NaH$ must be multiplied by 6 to balance sodium and hydrogen atoms.