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3 years ago

How many moles of MgCl2 are there in 337 g of the compound?

Physics

1 answer:

bixtya [17]3 years ago

4 0

3.51 Moles. I am pretty sure that is right.

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Which conclusion about the atom can be drawn from Rutherford’s gold foil experiment?

Drupady [299]

D. Rutherford found that the atom consists of a small positively charged nucleus.

6 0

3 years ago

Read 2 more answers

A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the

AleksAgata [21]

Answer:

acceleration = 2.4525‬ m/s²

Explanation:

Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²

Tension in the rope = T

Sol: m2 > m1

i) for downward motion of m2:

m2 a = m2 g - T

5 a = 5 × 9.81 m/s² - T

⇒ T = 49.05‬ m/s² - 5 a Eqn (a)‬

ii) for upward motion of m1

m a = T - m1 g

3 a = T - 3 × 9.8 m/s²

⇒ T = 3 a + 29.43‬ m/s² Eqn (b)

Equating Eqn (a) and(b)

49.05‬ m/s² - 5 a = T = 3 a + 29.43‬ m/s²

49.05‬ m/s² - 29.43‬ m/s² = 3 a + 5 a

19.62 m/s² = 8 a

⇒ a = 2.4525‬ m/s²

5 0

3 years ago

The force of gravity considers which two parts?

attashe74 [19]

Mass of object/source
Gravity
Fg=mg

3 0

3 years ago

A water hose is used to fill a large cylindrical storage tank of

ludmilkaskok [199]

Answer:

maximum possible speed by solving above equation for 7D is

$v_{max} = \sqrt{\frac{49}{5}gD}$

minimum possible value of speed for solving x = 6D is given as

$v_{min} = \sqrt{9gD}$

Explanation:

Let the nozzle of the hose be at the origin. Then the nearest part of the rim of the tank is at (, ) = (6, 2) and the furthest part of the rim is at (, ) = (7, 2).

The trajectory of the water can be found as follows:

$x = (v_o cos45) t$

$y = (v_o sin45) t - \frac{1}{2}gt^2$

Now from above two equations we have

$y = x - \frac{gx^2}{v_o^2}$

now we know that height of the cylinder is 2D so we have

$x - \frac{gx^2}{v_o^2} = 2D$

by solving above equation we have

$x = \frac{v_o^2 \pm v_o^2\sqrt{1 - \frac{8gD}{v_o^2}}}{2g}$

now we know that maximum value of x is 7D

so the maximum possible speed by solving above equation for 7D is

$v_{max} = \sqrt{\frac{49}{5}gD}$

minimum possible value of speed for solving x = 6D is given as

$v_{min} = \sqrt{9gD}$

6 0

3 years ago

What force is applied to a 60 kg person if it takes 7.8 seconds to reach a speed of 12.86 m/s from rest?

docker41 [41]

Answer:

drag

Explanation:

drag is the force that acts against any moving object.

if it takes him any amount of time to get from one speed to another, it is caused by drag.

3 0

2 years ago