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Mice21 [21]
3 years ago
10

A car traveling at 38 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is its acceleration?

Physics
1 answer:
asambeis [7]3 years ago
6 0

a=v/t

a=38/10

a=-3.8 m/s^2

You put the negative in front of 3.8 because it decelerated.

Hope it helps and is correct :)

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6 0
3 years ago
PLEASE ANYONE SOLVE THIS NOW FAST PLEASE IM IN A HURRY
m_a_m_a [10]

Hello,

<u>Solution for A:</u>

Force = 3.00N

Mass = 0.50 Kgs

Time = 1.50 Seconds

According to newton's second law of motion;

Force = Mass times Acceleration(a)

3.00 = 0.50 * a

a = 3.00/0.50 = 6.00 m/s^2

We know that acceleration = Velocity / time

So Velocity = time * acceleration = 1.50 * 6 = 9.00 m/s^2

<u>Solution for B:</u>

The net force = 4.00N - 3.00N = 1.00N to the left

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3 0
3 years ago
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