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solong [7]
3 years ago
14

The force of gravity considers which two parts?

Physics
1 answer:
attashe74 [19]3 years ago
3 0
Mass of object/source
Gravity
Fg=mg
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A tuning fork labeled 392 Hz has the tip of each of its two prongsvibrating with an amplitude of 0.600mma) What is the maximum s
DanielleElmas [232]

a) 1.48 m/s

The tuning fork is moving by simple harmonic motion: so, the maximum speed of the tip of the prong is related to the frequency and the amplitude by

v_{max}=\omega A

where

v_{max} is the maximum speed

\omega is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

\omega=2\pi f=2 \pi(392 Hz)=2462 rad/s, where f is the frequency

A=0.600 mm=6\cdot 10^{-4} m is the amplitude

Therefore, the maximum speed is

v_{max}=(2462 rad/s)(6\cdot 10^{-4}m)=1.48 m/s

b)  3.0\cdot 10^{-5} J

The fly's maximum kinetic energy is given by

K=\frac{1}{2}mv_{max}^2

where

m=0.0270 g=2.7\cdot 10^{-5} kg is the mass of the fly

v_{max}=1.48 m/s is the maximum speed

Substituting into the equation, we find

K=\frac{1}{2}(2.7\cdot 10^{-5}kg)(1.48 m/s)^2=3.0\cdot 10^{-5} J

7 0
3 years ago
Which device is used to convert electrical energy to mechanical energy?
algol13

Answer:

Generator

Hope it helps yah

7 0
3 years ago
Read 2 more answers
A flat, circular loop has 18 turns. The radius of the loop is 15.0 cm and the current through the wire is 0.51 A. Determine the
Ostrovityanka [42]

Answer:

The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.

Explanation:

Given;

number of turns of the flat circular loop, N = 18 turns

radius of the loop, R = 15.0 cm = 0.15 m

current through the wire, I = 0.51 A

The magnetic field through the center of the loop is given by;

B = \frac{N\mu_o I}{2R}

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

B = \frac{N\mu_o I}{2R} \\\\B = \frac{18*4\pi*10^{-7} *0.51}{2*0.15} \\\\B = 3.846 *10^{-5} \ T

Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.

6 0
4 years ago
A light beam approaches a plain mirror at an incident angle of 39
Paul [167]
Angle is 31 adding all sides
3 0
3 years ago
The mass of the Moon is 7.35 x 1022 kg, while that of Earth is 5.98 x 1024 kg. The average distance from the center of the Moon
Kryger [21]

Answer:

aaa

Explanation:

m_e = Mass of the Earth =  5.98 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r_1 = Distance from the center of the Moon to the center of Earth = 6371000 m

r_2 = Distance from the center of the earth center to sun center

m_m = Mass of moon = 7.35\times 10^{22}\ kg

M = Mass of sun = 1.989\times 10^{30}\ kg

F_1=G\frac{m_em_m}{r_1^2}\\\Rightarrow F_1=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 7.35\times 10^{22}}{(384000000)^2}\\\Rightarrow F_1=1.988\times 10^{20}\ N

F_2=G\frac{Mm_e}{r_1^2}\\\Rightarrow F_2=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 1.989\times 10^{30}}{(149.6\times 10^9+6371000+695.51\times 10^6)^2}\\\Rightarrow F_2=3.511\times 10^{22} N

\frac{F_1}{F_2}=\frac{1.988\times 10^{20}}{3.511\times 10^{22}}\\\Rightarrow \frac{F_1}{F_2}=0.00566\\\Rightarrow F_1=F_20.00566

Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center

4 0
4 years ago
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