If you would like to solve the system of equations, you can do this using the following steps:
4x^2 + 9y^2 = 72
2x - y = 4 ... 2x - 4 = y
_________
<span>4x^2 + 9y^2 = 72
</span><span>4x^2 + 9 * (2x - 4)^2 = 72
</span>4x^2 + 9 * (4x^2 - 16x + 16) = 72
4x^2 + 36x^2 - 144x + 144 = 72
40x^2 - 144x + 144 - 72 = 0
40x^2 - 144x + 72 = 0
10x^2 - 36x + 18 = 0
5x^2 - 18x + 9 = 0
(5x - 3) * (x - 3) = 0
1. 5x - 3 = 0 ... 5x = 3 ... x = 3/5
2. x = 3
<span>1. y = 2x - 4 = 2 * 3/5 - 4 = 6/5 - 20/5 = -14/5
2. y = 2x - 4 = 2 * 3 - 4 = 6 - 4 = 2
1. (x, y) = (3/5, -14/5)
2. (x, y) = (3, 2)
The correct result would be </span>(3/5, -14/5) and <span>(3, 2).</span>
Answer:g(X)=2x^2-10
Step-by-step explanation:
If a function f(x) is translated 'c' units down then the equation of the translated function be f(x)-c
Here, f(x) is translated 2 units down to obtain g(x).
Hence, we have
g(x)=f(x)-2
=2x^2-8-2
=2x^2-10
Answer:
its b
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Choose a point with a negative x coordinate and a positive y coordinate.
Step-by-step explanation:
The quadrants are labeled counter clockwise 1, 2, 3, and 4.
Quadrant I - has x and y coordinate both positive.
Quadrant 2 - has x coordinate negative and y coordinates positive.
Quadrant 3 - has x and y coordinates both negative.
Quadrant 4 - has x coordinates positive and y coordinates negative.
Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).
