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3 years ago

Calculate the molar solubility of CaSO4. Ksp = 7.10 x 10-5

Chemistry

2 answers:

zubka84 [21]3 years ago

4 0

Multiple or divide them

Aliun [14]3 years ago

4 0

<u>Answer:</u> The solubility of calcium sulfate is $8.43\times 10^{-3}M$

<u>Explanation:</u>

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of calcium sulfate follows:

$CaSO_4(aq.)\rightleftharpoons Ca^{2+}(aq.)+SO_4^{2-}(aq.)$

s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=s\times s$

We are given:

$K_{sp}=7.10\times 10^{-5}$

Putting values in above expression, we get:

$7.10\times 10^{-5}=s\times s\\\\s=\sqrt{7.10\times 10^{-5}}=8.43\times 10^{-3}M$

Hence, the solubility of calcium sulfate is $8.43\times 10^{-3}M$

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Answer:

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Explanation:

Given that:

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$\alpha = \sqrt{\frac{1.34*10^{-5}}{7.84*10^{-2}} }$

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