Question

Calculate the molar solubility of CaSO4. Ksp = 7.10 x 10-5

Answer 1

Multiple or divide them

Answer 2

Answer: The solubility of calcium sulfate is $8.43\times 10^{-3}M$

Explanation:

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of calcium sulfate follows:

$CaSO_4(aq.)\rightleftharpoons Ca^{2+}(aq.)+SO_4^{2-}(aq.)$

                            s                s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=s\times s$

We are given:

$K_{sp}=7.10\times 10^{-5}$

Putting values in above expression, we get:

$7.10\times 10^{-5}=s\times s\\\\s=\sqrt{7.10\times 10^{-5}}=8.43\times 10^{-3}M$

Hence, the solubility of calcium sulfate is $8.43\times 10^{-3}M$