A pudding would be considered as solid since the molecules are in an ordered state and they are close to each other which gives definite shape and volume for the pudding. This is also true for the bucketful of sand. Hope this answers the question.
Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For CaCl₂,
E.N of Chlorine = 3.16
E.N of Calcium = 1.00
________
E.N Difference 2.16 (Ionic Bond)
For C-H Bond in C₆H₁₂O₆,
E.N of Carbon = 2.55
E.N of Hydrogen = 2.20
________
E.N Difference 0.35 (Non-Polar Covalent Bond)
For C-O Bond in C₆H₁₂O₆,
E.N of Oxygen = 3.44
E.N of Hydrogen = 2.55
________
E.N Difference 0.89 (Polar Covalent Bond)
For O-H Bond in C₆H₁₂O₆,
E.N of Oxygen = 3.44
E.N of Hydrogen = 2.20
________
E.N Difference 1.24 (Polar Covalent Bond)
For MgO,
E.N of Oxygen = 3.44
E.N of Magnesium = 1.31
________
E.N Difference 2.13 (Ionic Bond)
For Na₂O,
E.N of Oxygen = 3.44
E.N of Sodium = 0.93
________
E.N Difference 2.51 (Ionic Bond)
For SiO₂,
E.N of Oxygen = 3.44
E.N of Silicon = 1.90
________
E.N Difference 1.54 (Polar Covalent Bond)
Result:
Compounds having Ionic Bonds are Na₂O, MgO and CaCl₂.
Answer:
The specific heat of the alloy
Explanation:
Mass of an alloy = 25 gm
Initial temperature = 100°c = 373 K
Mass of water = 90 gm
Initial temperature of water = 25.32 °c = 298.32 K
Final temperature = 27.18 °c = 300.18 K
From energy balance equation
Heat lost by alloy = Heat gain by water
[ - ] = ( - )
25 × × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)
This is the specific heat of the alloy.