Answer:
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Explanation:
The silver nitrate, AgNO₃, dissolves in water as follows:
AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)
The Ag⁺ reacts with Cl⁻ producing AgCl(s), a white insoluble salt. The net ionic equation that describes the formation of the precipitate is:
<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 /><h3 />
If the actual yield of sodium chloride from the reaction of 8.3 g of sodium and 4.5 g of chlorine is 6.4 g, what is the percent yield?
Answer : 2Na(s) + Cl2(g) → 2NaCl(s)
Explanation: Friend me!!!
7.30 x 10^-7 km. the others have 4 significant figures.
To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy.
The amount of energy required by an isolated, gaseous molecule in the electronic state of the ground to absorb in order to discharge an electron and produce a cation has been known as the ionization energy. The amount of energy required for every atom in a mole to drop one electron is most often given as kJ/mol.
Anything that causes electrically neutral atoms and molecules to gain or lose electrons in order to become electrically charged atoms as well as molecules .
Therefore, the "To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy."
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