Answer:
if i am not mistaken the volume is 7, because it only took that much space
The options are missing and they are;
A) the electric force increases because the balloon loses its charge.
B) the electric force increases because the distance increases.
C) the electric force decreases because the distance increases.
D) the electric force decreases because his hair loses its charge.
Answer:
Correct answer is option C - the electric force decreases because the distance increases.
Explanation:
The formula for electric force is;
F = k•q1•q2/r²
Where;
K is coulombs constant
q1 and q2 are particle charges
r is distance
So,looking at the formula given earlier, if we increase the distance, the denominator will increase and thus the Force will decrease.
So the correct option is option C
Answer:
discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC source
Explanation:
Bulbs can emit light in several ways:
* When the emission is carried out by the heating of its filament, the bulb is called incandescent, in general its spectrum is similar to that of a black body, this is a continuous spectrum with a maximum dependent on the fourth power of the temperature of the filament.
* The emission can be by atomic transitions, in this case there is a discrete spectrum formed by the spectral lines of the material that forms the gas of the lamp, in general for the yellow emission the most used materials are mercury and sodium or a mixture of they.
Consequently, as discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC type
Answer:
2. Dot Product
Explanation:
The calculation of the electric flux gives an scalar result.
When we tray to calculate how much electric field passes trough a surface, we are calculating a scalar value. Furthermore, the concept of flux requires the calculation of a scalar value.
Also it is necessary to take into account that the magnitude of the flux trough a surface depends of the inclination of the surface respect to the direction of the electric field. This is taken into account sufficiently by a dot product.
Then, the answer is:
2. Dot Product
