How much force is required to accelerate a 5 kg object at 5 m/s^2?
1 answer:
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The reference frequency in our case would be 392Hz, and since there is the possibility of the upper and lower range for the amount of beats per second that the two possible frequencies are heard would be
Therefore the two possible frequencies the piano wire is vibrating at, would be 396Hz and 388Hz
Answer:
V = 4.81 V
Explanation:
- As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
- We can calculate this loss, applying Ohm's law to the internal resistance, as follows:
- The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:
- We can solve for rint, as follows:
- When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:
- As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.