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Suppose that after walking across a carpeted floor you reach for a doorknob and just before you touch it a spark jumps 0.95cm fr

alexandr402 [8]

To solve this problem we will consider the definition of Minimum Energy, as the change between the minimum voltage and its distance. Mathematically it can be written as

$E_{min} = \frac{V_{min}}{r}$

Rearranging to find the Voltage,

$V_{min} = E_{min} \times r$

Replacing,

$V_{min} = (3.0) \times (0.95*10^4)$

$V_{min} = 28500V$

Therefore the minimum voltage needed between your finger and the doorknob to generate this spark is 28.5kV

8 0

3 years ago

A force can exist between two charged particles or objects even if they're as small as subatomic particles. Between which of the

aev [14]

I think it is a not sher

7 0

3 years ago

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A sample of gas has an initial volume of 4.5 L at a pressure of 754 mmHg . Part A If the volume of the gas is increased to 8.5 L

Firdavs [7]

Answer:

The pressure will be of 399.17 mmHg.

Explanation:

p1= 754 mmHg

V1= 4.5 L

p2= ?

V2= 8.5 L

p1*V1 = p2*V2

p2= (p1*V1)/V2

p2= 399.17 mmHg

6 0

4 years ago

A revolutionary war cannon, with a mass of 2260 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 109 m/s aft

Anton [14]

Answer:

The gain in velocity is 0.37m/s

Explanation:

We need solve this problem though the conservation of momentum. That is,

$m_1 v_1 = m_2 v_2$

$m_1=2260Kg\\m_2=15.5Kg\\v_2= 109m/s$

Using the equation to find $v_1$ ,

$v_1=\frac{m_2 v_2}{m_1}\\v_1=\frac{15.5*109}{2260}\\v_1= 0.7475$

Using the conservation of energy equation, we have,

$KE= \frac{1}{2}m*v^2$

$KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J$

$KE_{cannon}=\frac{1}{2}(2260)(0.7475)^2=631.39J$

$Total KE= 92077.75+13425530=92708.9J$

Now this energy over the cannonball

$KE=\frac{1}{2}m*v_2^2$

$92708.9=\frac{1}{2}15.5v_2^2$

$V_2 = 109.37m/s$

The gain in velocity is 0.37m/s

4 0

3 years ago

7. Navy use SONAR method to locate the position of submarine under water. The waves used in SONAR are A transverse waves. B elec

pshichka [43]

Answer:

A. transverse waves

vote me brainliest?? 5/5

thanks:)

8 0

3 years ago

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