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ollegr [7]
2 years ago
11

HELP HELP HELP help pls

Physics
1 answer:
GalinKa [24]2 years ago
7 0
Answer is A.) 40 m/km

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During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxima
vova2212 [387]

Answer:

The value  F  =  0.1396 \ N

Explanation:

From the question we are told that

   The volume blood  ejected is  V  =  65 \ cm^3  = 65*10^{-6} \  m^3

    The velocity of the blood ejected is  v  = 103 \  cm/s  = \frac{103}{100} = 1.03 \ m/s

    The density of blood is  \rho = 1060 \  kg/m^3

     The heart beat is R = 59 \  bpm(beats \  per \  minute) = \frac{59}{60}= 0.9833\ bps

The average force exerted by the blood on the wall of the aorta is mathematically represented as

      F  =  2 * \rho  *  V  *  R *  v

=>    F  =  2 * 1060  *  65*10^{-6}  *  0.9833 *  1.03

=>    F  =  0.1396 \ N

8 0
3 years ago
I’m still lost on this please help me on this I know it’s not D I got it wrong
RSB [31]

Before you even look at the questions, look over the graph, so you know what kind of information is there.

The x-axis is "time".  OK.  You know that as the graph moves from left to right, it shows what's happening as time goes on.

The y-axis is "speed" of something.  OK.  When the graph is high, the thing is moving fast.  When the graph is low, the thing is moving slow.  When the graph slopes up, the thing is gaining speed.  When the graph slopes down, the thing is slowing down.  When the graph is flat, the speed isn't changing, so the thing is moving at a constant speed.

NOW you can look at the questions.

OMG !  It's only ONE question:  What's happening from 'c' to 'd' ?  Well I don't know.  Perhaps we can figure it out if we LOOK AT THE GRAPH !

-- Between c and d, the graph is flat.  The speed is not changing.  It's the same speed at d as it was back at c .

What speed is it ?

-- Look back at the y-axis.  The speed at the height of c and d is 'zero' .

-- The 2nd and 4th choices are both correct.  From c to d, <em>the speed is constant</em>.  The constant speed is zero.  <em>The car is not moving</em>.

5 0
3 years ago
A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at -3.0 m/s.
Katarina [22]
Option B would be right one
according to momentum conservation
6600*2 = 13200kgm/s
5400*3 = 16200kgm/s
16200-13200 = 3000
now 6600-5400 = 1200 kg
thus 3000/1200 = 2.5 v
5 0
2 years ago
A _____ is a quantity that has magnitude and direction
Snezhnost [94]

vector is the answer of this blank

7 0
3 years ago
(25 pts) Estimate how much collector area and storage capacity would be required for an active solar hot-water system designed t
Aneli [31]

Answer:

The required  total area is 1.48 m²

Explanation:

Given that,

Latitude = 44+° N

New Mexico,

Latitude= 35+° N

Heat capacity = 4200 J/Kg°C

Temperature = 60°C

Let us assume the input temperature 22°C

Estimate volume of water 100 ltr for 4 person.

We need to calculate the heat

Using formula of heat

H=mc_{p}\Delta T

H=mc_{p}(T_{f}-T_{i})

Put the value into the formula

H=100\times4200\times(60-22)

H=15960\ KJ...(I)

Let solar radiation for 6 hours/day.

We need to calculate the total energy per unit area

Using formula of energy

E=1000\times6\times3600\ J/m^2

E=21600\ KJ/m^2

Let the efficiency of collector is 50 %

Then,  the total energy per unit area will be

E=21600\times\dfrac{50}{100}

E=10800\ KJ/m^2....(II)

We need to calculate the required total area

Using equation (I) and (II)

A=\dfrac{H}{E}

Where, H = heat

E = total energy

Put the value into the formula

A=\dfrac{15960}{10800}

A=1.48\ m^2

Hence, The required  total area is 1.48 m²

6 0
3 years ago
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