The skateboarder has a mass of 100 kg. When traveling downward from E to D, he reaches a velocity of 11 m/s. Calculate his kinet
ic energy at D (explain work and include units please).
(KE= ½ mv2)
(KE= ½ mv2)
1 answer:
6050 J is the kinetic energy at D
<u>Explanation:</u>
In physics, the object's kinetic energy (K.E) defined as the energy it possesses during movement. It can be defined as the required work to accelerate a certain body weight in order to rest at a certain speed. When the body receives this energy as it speeds up (accelerates), it retains this energy unless speed varies. The equation is given as,
Where,
m - mass of an object
v - velocity of the object
Here,
Given data:
m = 100 kg
v = 11 m/s
By substituting the given values in the above equation, we get
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Answer:
λ =365.4 nm
Explanation:
Boh's atomic model of the Hydrogen atom the energy of each level is
Eₙ = - 13.606 / n²
where the synergy is in electonvotes and the value of E₀ = 13.606 eV is the energy of the base state of hydrogen.
An atomic transition occurs when an electron goes from an excited state and joins everything of lower energy.
ED = 13.606 (1 / n₀² - 1 /)
we are going to apply this relationship to answer slash.
At the beginning of the studies of atomic transitions, each group did not consider having a different name
name Initial state
Lymman 1
Balmer 2
the final state is any other state sta the continuum that corresponds to n = inf
Let's look for the highest energy of the Balmer series
ΔE = 13.606 (1/2² - 1 /∞)
ΔE = 3.4015 eV
Let's use the Planck relation for the energy
E = h f = h c /λ
λ = h c / E
Let's reduce the energy to J
E = 3.4015 eV (1.6 10⁻¹⁹ J / 1 eV) = 5.4424 10⁻¹⁹
λ = 6.63 10⁻³⁴ 3 10⁸ / 5.4424 10⁻¹⁹
λ = 3.654 10⁻⁷ m
λ = 3,654 10⁻⁷ m (10⁹ nm / 1m)
λ =365.4 nm
this eta radiation in the ultraviolet range
The energy of a single photon is given by:
where
E is the energy
h is the Planck constant
f is the frequency of the light
The light in our problem has a frequency
, so the energy of each photon of that light is:
where
E is the energy
h is the Planck constant
f is the frequency of the light
The light in our problem has a frequency
Answer:
Explanation:
We know that speed is defined as distance moved per unit time hence expressed as where v is speed in m/s, d is distance in m and t is time in seconds. Making d the subject of the above formula then
Substituting 343 m/s for d and 10 s for t then
Therefore, the distance between speaker and deter is