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lukranit [14]
3 years ago
10

How do you balance AlC3+H2O➡️Al(OH)3+CH4?

Chemistry
1 answer:
Alex17521 [72]3 years ago
5 0
Info: Al(oh)3 might be an improperly capitalized: Al(OH)3
Error: Some elements or groups in the reagents are not present in the products: O
Error: equation Al4C3+H2O=Al(oh)3+CH4 is an impossible reaction
Please correct your reaction or click on one of the suggestions below:
Al4C3 + H2O = Al(OH)3 + CH4
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Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
1 year ago
How many electrons are in their outer shell?
quester [9]
Is there an attachment because it depends on the element.
5 0
3 years ago
PLEASE HELP ASAP ESSAY WORTH 15 POINTS! ONLY GENIUS!
Sliva [168]

Answer:

According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products.

Explanation:

5 0
3 years ago
A person tries to heat up her bath water by adding 5.0 l of water at 80c to 60 l of water at 30c. what is the final temperature
Sophie [7]
We can calculate the final temperature from this formula :

when Tf = (V1* T1) +(V2* T2) / (V1+ V2)

when V1 is the first volume of water = 5 L 

and V2 is the second  volume of water = 60 L

and T1 is the first temperature of water in Kelvin = 80 °C +273 = 353 K

and T2 is the second temperature of water in Kelvin =  30°C + 273= 303 K

and Tf is the final temperature of water in Kelvin 

so, by substitution:

Tf = (5 L * 353 K ) + ( 60 L * 303 K) / ( 5 L + 60 L)

     = 1765 + 18180 / 65 L

     = 306 K
     = 306 -273 = 33° C

8 0
2 years ago
Why isnt my grandma talking to me
Rufina [12.5K]

Answer:

She saw you at the elderly N*de swimming event.

Explanation: You tell me...

4 0
2 years ago
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