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4 years ago

10

How do you balance AlC3+H2O➡️Al(OH)3+CH4?

1 answer:

Alex17521 [72]4 years ago

5 0

Info: Al(oh)3 might be an improperly capitalized: Al(OH)3
Error: Some elements or groups in the reagents are not present in the products: O
Error: equation Al4C3+H2O=Al(oh)3+CH4 is an impossible reaction
Please correct your reaction or click on one of the suggestions below:
Al4C3 + H2O = Al(OH)3 + CH4

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GET IT RIGHT FOR BONUS

storchak [24]

Answer:

Sand

Explanation:

with salt distillation will work, heat the solution and collect the water in a seperate beaker

With sugar you do the same, boil away the water and collect the water vapour, you'll be left with sugar in the original container and water if you collected it

Use a fraction of column and heat the solution, the alcohol will be seperated out

Sand is the only one that uses mechanical filtration

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3 years ago

Predict the products of the double replacement reaction 2KOH + H2504 --?

Darina [25.2K]

What the heck is this 9287262729272727272727171

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3 years ago

In which of the following does the land being moved contin approximately 60% water

sp2606 [1]

Answer:

C

Explanation:

The answer is C because only that amount can move

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3 years ago

Read 2 more answers

What is the molarity (M) of the following solutions?

Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

= 27 + 3(16 + 1)

= 27 + 3(17) = 27 + 51

= 78 g/mole

$Al(OH)_3$ = 78 g/mole

Given mass= 19.2 g/mole

$Mole = \frac{Given\ mass}{Molar\ mass}$

$Mole = \frac{19.2}{78}$

Moles = 0.246

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

Volume = 280 mL = 0.280 L

$Molarity = \frac{0.246}{0.280)}$

Molarity = 0.879 M

Molarity = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

$Mole = \frac{235.9}{119}$

Moles = 1.98

Volume = 2.6 L

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

$Molarity = \frac{1.98}{2.6)}$

Molarity = 0.762 M

Molarity = 0.76 M

4 0

3 years ago

How does one calculate the pH of a solution? O A. The pH is the product of [H+] and [OH-]. O B. The pH is the negative log of [O

blagie [28]

Answer:

I believe it is A

Explanation:

pH = -log[H+] and pOH = -log[OH−].

8 0

3 years ago