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3 years ago

What is the total area of the figure below? i need help

Mathematics

1 answer:

kap26 [50]3 years ago

6 0

Total area is 1680 sq. inches.

Area = width * height

I noticed that the figure can form 10 rectangles with a width of 14 inches and a height of 12 inches.

Area = 14 inches * 12 inches
Area = 168 sq. inches ** This in only the Area of 1 rectangle.

To get the total area of the figure. Multiply Area by the 10 rectangles that can be formed in the figure.

168 sq. inches * 10 = 1680 sq. inches.

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uranmaximum [27]

Answer:

D = 12.94 m

Step-by-step explanation:

Coordinates of first tree = A(0,8)

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We need to find the distance between the two trees. We can find it using distance formula for coordinates as follows :

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

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Now using distance formula,

$D=\sqrt{(12-0)^2+(4-8)^2}\\\\=\sqrt{144+16} \\\\=12.64\ m$

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3 years ago

87/80 into a mixed number in lowest terms no links or ill report.

svp [43]

Answer:

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Step-by-step explanation:

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3 years ago

If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle

melamori03 [73]

Let's assume they meant C=40 degrees. With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

$AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C$

$AB^2 = AC^2 + BC^2 - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ$

$AB = \sqrt{ 169 - 120 \cos 40 ^\circ} \approx 8.77921789$

The area is $\frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628$

The circumradius is $r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) } = 6.829019329$

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4 years ago

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kiruha [24]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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