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professor190 [17]
3 years ago
7

Describe why some acids are strong while other acids are weak

Chemistry
1 answer:
Andrej [43]3 years ago
8 0

Answer:

<h2><em>I hope this help you. Mark me as brainliest and rate please</em></h2>

Explanation:

<em>the terms strong and weak as applied to acids. As a part of this it defines and explains what is meant by pH, Ka and pKa. </em>

<em> </em>

<em>It is important that you don't confuse the words strong and weak with the terms concentrated and dilute. </em>

<em> </em>

<em>As you will see below, the strength of an acid is related to the proportion of it which has reacted with water to produce ions. The concentration tells you about how much of the original acid is dissolved in the solution. </em>

<em> </em>

<em>It is perfectly possible to have a concentrated solution of a weak acid, or a dilute solution of a strong acid. </em>

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If a piece of matter changes shape, how does its mass change?
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The law of conservation of mass states that matter cannot be created nor destroyed the answer would be D. It remains the same
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3 years ago
Use the following half-reactions to construct a voltaic cell:
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<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

4 0
3 years ago
Part 1: A cylinder containing 20.0 L of compressed nitrogen is connected to an empty (evacuated) vessel with an unknown volume.
baherus [9]

Answer:

The volume of the vessel is 250 L

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Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

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V₂ = ?

P₁ = 25 atm

P₂ = 2 atm

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{25}\times {20.0}={2}\times {V_2}

{V_2}=\frac {{25}\times {20.0}}{2}\ L

{V_2}=250\ L

<u>The volume of the vessel is 250 L.</u>

According to Dalton's law of partial pressure:-

P_{H_2}=Mole\ fraction\times Total\ Pressure

So, according to definition of mole fraction:

Mole\ fraction\ of\ H_2=\frac {n_{H_2}}{n_{H_2}+n_{He}}

Also,

Mole fraction of H₂ = 1 - Mole fraction of He = 1 - 0.75 = 0.25

So,

Total pressure = 756 torr

Thus,

P_{H_2}=0.25\times 756\ torr

<u>Partial pressure of hydrogen = 189 torr.</u>

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3 years ago
In calorimetry, energy is measured through heat transfer from one substance to
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I think you forgot to add a picture?
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Which of these sets of elements has similar properties?
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Elements in a group have similar properties. 

<span>strontium, magnesium, calcium, beryllium  are the answers because they belong to same group (2nd group).


</span>
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2 years ago
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