Answer:
Which of the following
properties distinguishes a solution
oversaturated with a dilute?
- The supersaturated solution is one in which the solvent has dissolved more solute than it can dissolve in the saturation equilibrium. The solute can be a solid, or a gas. The molecules of the solvent surround those of the solute and seek to open space between themselves to be able to harbor more amount of solute.
- A dilute solution is a solution that has not reached the maximum concentration of solute dissolved in a solvent. The additional solute will dissolve when added in a dilute solution and will not appear in the aqueous phase.
It is considered a state of dynamic equilibrium where the speeds in which the solvent dissolves the solute are greater than the recrystallization rate.
Answer:
The town should find a new source of water.
Explanation:
Step 1: Convert the mass of copper to milligrams
We will use the conversion factor 1 g = 1000 mg.
0.002 g × (1000 mg/1 g) = 2 mg
Step 2: Convert the mass of solution to kilograms
We will use the conversion factor 1 kg = 1000 g.
1000 g × (1 kg/1000 g) = 1 kg
Step 3: Calculate the concentration of Cu in ppm (mg/kg)
2 mg/1 kg = 2 ppm
This is over 1.3 ppm, so the town should find a new source of water.
Answer:
1. Option c. bimolecular
2. Option b. termolecular
3. Option a. unimolecular
Explanation:
The initial report of the team formed by PURE may contain findings similar to the processes used in the disinfection of the water. Usual cases of ammonia presence in water are due to chloramine disinfection process. Also, they should also look into the storage of their facility and the end user which may also have a window of contamination.
Answer: The pressure in torr is 461 torr
Explanation:
To calculate the relation of density and molar mass of a compound, we use the ideal gas equation:
PV=nRT
P = pressure
V = Volume
n = number of moles
R = gas constant = 0.0821 Latm/Kmol
T = temperature =
Number of moles (n) can be written as:
where, m = given mass
M = molar mass = 44 g/mol
where,
where d = density = 2.54 g/L
The relation becomes:
PM=dRT
(760torr=1atm)
Thus the pressure in torr is 461 torr
