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3 years ago

What did Kwang Jeon discover when researching amoeba infected by bacteria?

1 answer:

defon3 years ago

6 0

Kwang Jeon observed that Amoeba had been attacked by a bacterial infection, and lots of the Amoeba had died. However, some survived and continued to reproduce. After investigating the remaining Amoeba and their offspring, he noticed they were very healthy. He thought maybe they were able to fight off the bacteria, but instead, he found they were still infected with the bacteria but were not dying. The bacteria were no longer making the Amoeba sick. Then, he killed off the bacteria using antibiotics and was surprised to see that the Amoeba also died. It seemed the Amoeba and bacteria had formed a relationship in which they both needed each other to survive. After researching, Jeon found that the bacteria made a protein that the Amoeba needed to survive.

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Chemistry question! Please explain!

Ilya [14]

There are no numbers provided so I will try to explain the equation. If you want to find the percent error you would do theoretical (the number it’s supposed to be) minus experimental (the number you got in the experiment) over the theoretical value (same as the first one.) You must multiply this by 100 in order to show the actual percentage rather than very low decimals. You want the percent error to be as low as possible because the lower it is the less mistakes happened. Mistakes can include too much/less of solvent, solution, or the glassware wasn’t clean enough, and much much more.

I hope this helps!
Please mark the brainliest if it does! (:

6 0

3 years ago

How are sound waves different from the waves in the sea or the ripples on water???

nirvana33 [79]

Answer:

water wave shake energy over the surface to the sea, while sound waves thump energy trough the body of the air. sound waves are compression waves

Hope this helps :)

5 0

3 years ago

Pluto is a planet True False

koban [17]

Answer:

False

Explanation:

It's classified as a dwarf planet, but not technically a planet.

6 0

3 years ago

Two tons of water is pumped into a tank 15 ft. High in 5 minutes. Determine the power output of the pump. (Note: One ton is equa

Semmy [17]

Answer:

200 lb•ft/s

Explanation:

From the question given above, the following data were obtained:

Force (F) = 2 tons

Time (t) = 5 mins

Height (h) = 15 ft

Power (P) =?

Next, we shall convert 2 tons to pound. This can be obtained as follow:

1 ton = 2000 lb

Therefore,

2 tons = 2 × 2000

2 tons = 4000 lb

Next, we shall convert 5 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

5 mins = 5 × 60

5 mins = 300 s

Finally, we shall determine the power of the pump. This can be obtained as follow:

Force (F) = 4000 lb

Time (t) = 300 s

Height (h) = 15 ft

Power (P) =?

P = F × h / t

P = 4000 × 15 / 300

P = 60000 / 300

P = 200 lb•ft/s

Thus, the power of the pump is 200 lb•ft/s

5 0

2 years ago

Given a fixed amount of gas held at constant pressure, calculate the volume it would occupy if a 2.00 L sample were cooled from

aliina [53]

Answer:

1.82 L

Explanation:

We are given the following information;

Initial volume as 2.0 L
Initial temperature as 60.0°C
New volume as 30.0 °C

We are required to determine the new volume;

From Charles's law;

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Where, $V_1 and V_2$ are initial and new volume respectively, while $T_1 and T_2$ are initial and new temperatures respectively;

$T_1= 333 K$

$T_2=303K$

$V_1 =2.0L$

Rearranging the formula;

$V_2=\frac{V_1T_2}{T_1}$

$= \frac{(2.0L)(303K)}{333K} \\=1.820 L$

Therefore, the new volume that would be occupied by the gas is 1.82 L

7 0

3 years ago