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Lemur [1.5K]
3 years ago
7

The roof of a house seen from the front is an isosceles triangle \Delta ABC ΔABC with base 14.5 m and sides of length 8.5 m. Fin

d how high above line [BC] the vertex A is​

Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

4.4 m

Step-by-step explanation:

Draw the height of the triangle (perpendicular line from point A to line BC).  Since ABC is an isosceles triangle, the height is a perpendicular bisector, so it splits the triangle into two congruent right triangles.

Use Pythagorean theorem to find the height.

c² = a² + b²

(8.5 m)² = (14.5/2 m)² + h²

h ≈ 4.4 m

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3 years ago
What is the distance between (-5, -8) and (-1, -16)
yulyashka [42]

(4,-8)

Step-by-step explanation:

from -5 to -1 you would have to count from 1 to 4. and do the same for -8 to -16

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3 years ago
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Two cars are traveling north along a highway. The first drives at 40 mph, and the second, which leaves 3 hours later, travels at
belka [17]

Answer:

Step-by-step explanation:

We will make a table and fill it in according to the information provided. What this question is asking us to find, in the end, is how long did it take the cars to travel the same distance. In other words, how long, t, til car 1's distance = car 2's distance. The table looks like this:

              d     =      r     *     t

car1

car2

We can fill in the rates right away:

             d       =      r     *     t

car1                       40

car2                       60

Now it tells us that car 2 leaves 3 hours after car 1, so logically that means that car 1 has been driving 3 hours longer than car 2:

            d     =      r      *      t

car1                     40         t + 3

car2                     60           t

Because distance = rate * time, the distances fill in like this:

                   d      =      r      *      t

car1    40(t + 3)    =      40        t+3

car2          60t     =       60         t

Going back to the interpretation of the original question, I am looking to solve for t when the distance of car 1 = the distance of car 2. Therefore,

40(t+3) = 60t and

40t + 120 = 60t and

120 = 20t so

t = 6 hours.

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