Answer:
the first box
fourth box
fifth box and last box
Step-by-step explanation:
Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
3,301927249 = ³√36
As discussed in one of my videos on my channel [USERNAME: MATHEMATICS WIZARD] on the Six Rational Exponential Rules, this one states that with a numerator of 1 in the exponent, you take the multiplicative inverse [reciprocal] of the fraction, and set the whole number equal to the root, bringing your a inside the radical, which is 36.
ⁿ√aᵐ = aᵐ\ⁿ → works for both: numerator ≥ 1
I am joyous to assist you anytime.
Answer:
Yes they are.
They are congruent because they have two equal angles and one equal side
Scientific notation:
5.0209003 x 10^4
