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denpristay [2]
4 years ago
5

4 different balls, 3 are distinct. how many combinations

Mathematics
1 answer:
Firlakuza [10]4 years ago
6 0
You can only change them 16 times.

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In a particular region, for families with a combined income of $75,000 or more, 15% of these families have no children, 35% of t
SCORPION-xisa [38]

Answer:

The probability distribution for x:"number of children per family for this income group" is:

\text{P(x=0)}=0.15\\\\\text{P(x=1)}=0.35\\\\\text{P(x=2)}=0.45\\\\\text{P(x=3)}=0.05\\\\

Step-by-step explanation:

With the information given we have the relative frequencies of each category.

We know:

\text{P(x=0)}=0.15\\\\\text{P(x=1)}=0.35\\\\\text{P(x=2)}=0.45\\\\\text{P(x=3)}=0.05\\\\

7 0
3 years ago
Sarah answered 24 questions on her test correctly and earned an 80%. How many questions were on the test?
MaRussiya [10]

Answer:

43 questions in total

Step-by-step explanation:

the original equation with the unknown (total number of questions on the test) will look like this

\frac{total \: number \: of \: questions \: on \: exam}{24 \: answered \: questions}  = 80\%

we know this because to work out a percentage in the 1st place you need the total ÷ number (in this case it's ÷ how many questions out of the total she did answer)

now you rearrange.

you need to move the 24 to get the total on it's own here's how you do it

\frac{tot \: num \: of \: qs}{24}  \times 24 = 80\% \times 24

what you do to one side of equation you have to do to the other. the 24 and 24 on the left will cancel because 24÷24=1 and we don't write

got mum of Q's x 1= 80 x 24

now you convert % to decimal

80\% \times 100 = 0.80

replace

tot \: num \: qs \:  = 24 \times 0.80 = 19

now you take the original and + the 19

24 + 19 = 43

therefore there are a total of 43 questions on the exam

5 0
4 years ago
Simplify (4xy^2)^3(xy)^5<br><br>A. 64x^8y^11<br>B. 64x^15y^30<br>C. 12x^2y^11<br>D. 12x^8y^11<br>​
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3 years ago
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