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grigory [225]
3 years ago
12

Help me please :).........

Mathematics
1 answer:
VikaD [51]3 years ago
5 0
C I believe it not so sure
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Identify the properties used for the first two steps in simplifying 6ab2 + 4a2b – 3ab2 + 3a2b – 2a2b2.
Kryger [21]
The expression 6ab^2+4a^2b-3ab^2+3a^2b-2a^2b^2 has two similar pairs of <span>conjunctions.
</span>
1. Rewrite this expression as
6ab^2+4a^2b-3ab^2+3a^2b-2a^2b^2=
=(6ab^2-3ab^2)+(4a^2b+3a^2b)-2a^2b^2
and then 
2. add the similar <span>conjunctions
</span><span>
</span><span>(6ab^2-3ab^2)+(4a^2b+3a^2b)-2a^2b^2=3ab^2+7a^2b-2a^2b^2.</span><span>
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3 0
3 years ago
Read 2 more answers
30 POINTS!
Dafna1 [17]

Answer:

Step-by-step explanation:

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6 0
3 years ago
$1210 is invested in an account earning 11.5% interest compounded monthly. What is the balance at the end of 13 years? Group of
kap26 [50]

Answer:

Final amount = $5357.52

Step-by-step explanation:

Formula to be used,

Final amount = \text{Initial amount}\times (1+\frac{r}{n})^{nt}

Here, n = number of compounding in a year

t = Duration of investment

Now we substitute the given values in the question.

Final amount = 1210(1+\frac{0.115}{12})^{12\times 13}

                      = 1210(1.009583)^{156}

                      = 1210(4.4277)

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6 0
3 years ago
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Kipish [7]

Answer:

the second option (9,11,8)

Step-by-step explanation:

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If h(x) = (- 2x + 5)/4 find h(3/2)
Olenka [21]

Answer:

0.5

Step-by-step explanation:

just plug in the number in the x place.

8 0
3 years ago
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