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Jet001 [13]
2 years ago
7

A 4 V power source is connected in parallel to four resistors: 1, 2, 2, and 3. Find the total current.

Physics
1 answer:
Keith_Richards [23]2 years ago
4 0

Answer:

Explanation:

Equivalent resistance is 1 / ((1/1) + (1/2) + (1/2) + (1/3)) = 3/7 Ω

I = V/R = 4(7/3) = 28/3 = 9.3 A    

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In which wavelength region(s) would we need to carry out observations in order to study the accretion disk around a white dwarf
Inga [223]

In “Ultraviolet light” and “X-ray” light wavelength regions are needed to carry out observations to study the “accretion disk” around “a white dwarf” in a “binary system”.

<u>Explanation</u>:

Occurrence of an accretion disk is due to presence of diffuse material around a white dwarf in orbital motion. White dwarf is constituted from electron-degenerate matter therefore also called as degenerate dwarf in binary system. Frictional forces and gravitational forces are responsible to compress and high “temperature” of the material, results with emission of “electromagnetic radiation”. “Accretion disks” of white dwarf radiate in the UV-rays and X-rays wavelength region of spectrum.

7 0
3 years ago
URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (29pt
Furkat [3]

Chemical=B

Mechanical=C

Nuclear=A

Electromagnetic=D

Thermal=E

I think these are right but if not I’m sorry

Hope I helped :]

5 0
2 years ago
Read 2 more answers
A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What
Sedbober [7]

Answer:

377 nm

Explanation:

Number of lines per meter is, N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}

Grating element is, d=\frac{1}{N}

=1.8868 \times 10^{-6} \mathrm{~m}[tex]&#10;Order is, n=5&#10;Condition for maximum intensity is, [tex]d \sin \theta=n \lambda

 \lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\&#10;&=0.377 \times 10^{-6} \mathrm{~m} \\&#10;&=377 \mathrm{~nm}

7 0
2 years ago
The mass of a large car is 1000 kg. How much force would be required to accelerate the car at a rate of 3 m/sec2?
Lubov Fominskaja [6]

Answer: 3000 Newton

Explanation:

Mass of large car = 1000 kg.

Acceleration of the car = 3 m/sec2

Force = ?

Recall that force is the product of mass of an object and the acceleration by which it moves.

Thus, Force = Mass x Acceleration

Force = 1000 kg x 3 m/sec2

= 3000 Newton

Thus, 3000 Newton of force would be required to accelerate the car

8 0
3 years ago
A bowling ball weighing 71.2 N is attached to the ceiling by a 3.30 m rope. The ball is pulled to one side and released; it then
wolverine [178]

Answer:

a. The acceleration of the bowling ball is 9.5 m/s² toward the center

b.  The tension in the rope is 140.24 N

Explanation:

given information:

ball weight,  W = 71.2 N

the length of rope, R = 3.30 m

ball speed, v = 5.60 m/s

a. The acceleration of the bowling ball, α

α = \frac{v^{2} }{R}

where

α = the acceleration

v = the speed

R = radius

thus

α = \frac{v^{2} }{R}

  = \frac{5.60^{2} }{3.3}

  = 9.5 m/s² toward the center

b. The tension in the rope?

according to the Newton's second law

ΣF = m a

where

F = force

m = mass

a = acceleration

so,

ΣF = m a

T - W = m a

T = m a + W

  = (W a/g) + W

  = (71.2 x 9.5/9.8) + 71.2

  = 140.24 N

4 0
2 years ago
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