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melisa1 [442]
3 years ago
14

I need help with this problem on science 8th grade here is the picture of the assignment place help me

Physics
2 answers:
N76 [4]3 years ago
8 0
D & C are the answers .
Leni [432]3 years ago
7 0

Answer:

the first one is D

Explanation:

so if the others u put are right the the second would be c

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A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When th
aev [14]

Answer:

x_2=1.60m

Explanation:

From the Question We are told that

Initial Force F_1=5800N

Final Force F_2=6500N

Distance between the front and rear wheels \triangle x=3.20 m

Since

 \triangle x=3.20 m

Therefore

 x_1+x_2=3.20

 x_1=3.20-x_2

Generally the equation for The center of mass is at x_2 is mathematically

given by

 x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}

 x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}

 2*F_1*x_2 =3.20F_1

 x_2=1.60m

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2 years ago
Need the answer for question 5 :)
kykrilka [37]

Answer:

1 B. Convert v from km/min to m/s ( show work and units

3 0
3 years ago
Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated
Artemon [7]

Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN

Explanation: To find the answer we need to know more about the Newton's law of gravitation.

<h3>What is Newton's law of gravitation?</h3>
  • Gravitation is the force of attraction between any two bodies.
  • Every body in the universe attracts every other body with a force.
  • This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between these two masses.
  • Mathematically we can expressed it as,

                        F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2

<h3>How to solve the problem?</h3>
  • Here, we have given with the data's,

                      M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m

  • Thus, the force of attraction between these two bodies will be,

               F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN

Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.

Learn more about the Newton's law of gravitation here:

brainly.com/question/28045318

#SPJ4

6 0
1 year ago
If Ike notices that there is a new moon tonight, when should he expect there to be a new moon again?
podryga [215]
Whatever phase of the moon Ike sees, he can expect to see
the same phase of moon again, after 29.53 days later.
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3 years ago
Physical science semester B exam 66 problems , please don’t delete I’m on my last leg I need this please god help me
krek1111 [17]
HI!! If you need answers to your exam, then go to https://quizlet.com/ then search for what you need!! I hope this helps I am not sure what your exam is for, and I don't have enough info to tell you all the answers, but hopefully, this will help you!!

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3 years ago
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