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3 years ago

A bike moves. 50 m in 10 seconds calculate the speed of the bike

Physics

1 answer:

vagabundo [1.1K]3 years ago

5 0

Answer:

We know that

Speed = Distance/ Time

Explanation:

Distance is 50 m
Time is 10 seconds

Speed = 50/10

= 5 m/s

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Astronaut Rob leaves Earth in a spaceship at a speed of 0.960c relative to an observer on Earth. Rob's destination is a star sys

xxMikexx [17]

Answer:

A) 15.0 years

Explanation:

Due to the distance to the star system is in light-year units, we can compute the time by using:

$t=\frac{d}{v}=\frac{14.4 l-y}{0.960}=15l-y$

then, Rob will take to complete the trip about 15 light-years.

hope this helps!!

3 0

3 years ago

At a certain instant, a rotating turbine wheel of radius RR has angular speed ωω (measured in rad/srad/s). What must be the magn

jonny [76]

Answer:

Explanation:

The magnitude of the acceleration makes an angle of 30° with the tangential velocity.

Resolving the acceleration to tangential and radial acceleration

at = aCos30 = √3a/2

ar = aSin30 = ½a

a = 2•ar

Then, the tangential acceleration is the linear acceleration, so the relationship between the tangential acceleration and angular acceleration is given as:

at = Rα

Then, α = at/R

since at = √3a/2

Then, α = √3 at/2R, equation 1

The radial acceleration is given as

ar = ω²R

Note that, at² + ar² = a²

at = √(a²-ar²)

Back to equation 1

α = √3 at/2R

α = √3√(a²-ar²)/2R

α = √3√(a²-(w²R)²)/2R

α = √3(a²-w⁴R²) / 2R

Also, a = 2•ar = 2w²R

Then,

α = √3((2w²R)²-w⁴R²) / 2R

α = √3(4w⁴R²-w⁴R²) / 2R

α = √3(3w⁴R²) / 2R

α = √9w⁴R² / 2R

α = 3w²R / 2R

α = 3w²/2

7 0

3 years ago

A particle of charge of +3.40 ✕ 10−6 C is 17.5 cm distant from a second particle of charge of −2.00 ✕ 10−6 C. Calculate the magn

Karolina [17]

Answer:

0.47 N

Explanation:

q1 = 3.4 x 10^-6 C

q2 = 2 x 10^-6 C

d = 17.5 cm = 0.175 m

The electrostatic force is given by

$F=\frac{Kq_{1}q_{2}}{d^{2}}$

$F=\frac{9\times10^{9}\times3.4\times 10^{-6}\times 2\times 10^{-6}}{0.175\times 0.175}$

F = 0.47 N

Thus, the force is 0.47 N.

5 0

3 years ago

When you’re driving a golf ball, a good "follow-through" helps to increase the distance of the drive. A good follow-through mean

Natali [406]

Answer:

$v_{f}$ = F Δt / m

Explanation:

The impulse theorem and momentum is

I = Δp

F Δt = m $v_{f}$ - m v₀

Before touching the ball is without movement, the force is represented by the kinetic energy of the club when it reaches the bottom of the path, so if this force is constant, the time [or the duration of the blow is directly proportional to the speed that the ball acquires.

$v_{f}$ = F Δt / m

The higher this speed, the greater the distance traveled.

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4 years ago

#1 How fast does an object need to travel to stay in orbit for one second?

fenix001 [56]

19685 mph to stay in orbit or 8 kilometers per second to stay in orbit if this dose not help tell me

8 0

3 years ago