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rewona [7]
3 years ago
11

How many atoms are in 0.075 mol of titanium?

Chemistry
2 answers:
Annette [7]3 years ago
7 0
The mass of titanium is = 47,867 g/1mol

Applying the rule of avrogado

1mol _______ 6,023 × 10^(23) at

0,075mol ___ x


X . 1mol = 0,075mol . 6,023 . 10^(23)at

X = 0,075 . 6,023 . 10^(23) at

X = 4,51 . 10^(22) atoms

Hope this helps
aleksley [76]3 years ago
7 0

<u>Answer:</u> The number of atoms in given amount of titanium are 4.52\times 10^{22}

<u>Explanation:</u>

We are given:

Moles of titanium = 0.075 moles

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of atoms

So, 0.075 moles of titanium will contain = (0.075\times 6.022\times 10^{23})=4.52\times 10^{22} number of atoms

Hence, the number of atoms in given amount of titanium are 4.52\times 10^{22}

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What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
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Answer:

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Explanation:

ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

In our case we have:

mass of MgBr₂ = 12.41 g

volume of water (which is equal to the final solution volume) = 2.55 L

Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

then         X g of MgBr₂ are dissolved in 1 L of water

X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂

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4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

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