a candidate received 430,500 of the 750,000 ballots cast in an election. What percent of the vote did this candidate receive?

NEED ANSWER ASAP- FOR FINALS

blagie [28]

Answer:

Width - 12ft Length - 30ft

Step-by-step explanation:

Width is 12ft

Length is 30ft

Depth is 6ft

The length, 30ft, is 2.5 times longer than the width which is 12 ft which confirms the two dimensions to be correct.

When you multiply all three of the dimensions of the swimming pool you will get 2940 cubic feet

8 0

3 years ago

What is the volume of the cone? cone v = one-third b h startfraction 70 over 3 endfraction pi centimeters cubed startfraction 14

Bas_tet [7]

Using the assumed values, the volume of the cone is $V = \frac {250}3\pi$

<h3>How to determine the volume of the cone?</h3>

The volume of a cone is calculated using:

$V = \frac 13\pi r^2h$

The parameters are not given.

So, we use the following assumed values

Radius, r = 5

Height, h =10

Using the assumed values, we have:

$V = \frac 13\pi * 5^2 * 10$

Evaluate the product

$V = \frac {250}3\pi$

Hence, using the assumed values, the volume of the cone is $V = \frac {250}3\pi$

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

7 0

1 year ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0

3 years ago

Prove algebraically that 0.5 recurring = 5/9

weeeeeb [17]

Answer:

see explanation

Step-by-step explanation:

We require 2 equations with the recurring part after the decimal point.

Let x = 0.555..... → (1)

Multiply both sides by 10, then

10x = 5.555..... → (2)

Subtract (1) from (2) thus eliminating the recurring decimal

(10x - x) = (5.5555 - 0.5555 ), that is

9x = 5 ( divide both sides by 9 )

x = $\frac{5}{9}$

5 0

2 years ago

How many six-digit odd numbers are possible if the left digit cannot be zero?

melisa1 [442]

We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>

6 0

2 years ago