Nuclear energy can be used to power ______

Which statement best describes how the distance from a large river affects an area’s climate in the summer?

Montano1993 [528]

Answer:

Regions near rivers have water surfaces that rapidly change in temperature from cold to hot.

you have your own answer i only selected which is suitable for me . none of them is wrong they re excellent

3 0

3 years ago

Read 2 more answers

Water (rhoH20 = 1000.0 kg/m3 ) flows through a garden hose that goes up a step 20.0 cm high. The cross-sectional area of the hos

Soloha48 [4]

Answer:

P₂ = 138.88 10³ Pa

Explanation:

This is a problem of fluid mechanics, we must use the continuity and Bernoulli equation

Let's start by looking for the top speed

Q = A₁ v₁ = A₂ v₂

We will use index 1 for the lower part and index 2 for the upper part, let's look for the speed in the upper part (v2)

v₂ = A₁ / A₂ v₁

They indicate that A₂ = ½ A₁ and give the speed at the bottom (v₁ = 1.20 m/s)

v₂ = 2 1.20

v₂ = 2.40 m / s

Now let's write the Bernoulli equation

P₁ + ½ ρ v₁² + ρ g y₁ = P2 + ½ ρ v₂² + ρ g y₂

Let's clear the pressure at point 2

P₂ = P₁ + ½ ρ (v₁² - v₂²) + ρ g (y₁-y₂)

we put our reference system at the lowest point

y₁ - y₂ = -20 cm

Let's calculate

P₂ = 143 10³ + ½ 1000 (1.20² - 2.40²) + 1000 9.8 (-0.200)

P₂ = 143 103 - 2,160 103 - 1,960 103

P₂ = 138.88 10³ Pa

3 0

4 years ago

Describe how private citizens have a voice in which projects the federal government will fund

erastovalidia [21]

<span>Two main ways, free elections, casting your vote for the candidate supporting your goals. Second, Lobbying the sitting gov.</span>

3 0

3 years ago

If you walk 3 meters north and then 4 meters west, what is the magnitude of your displacement?

ankoles [38]

S^2=3^2+4^2
S^2=9+16
S^2=25
S=√25
S=5m

7 0

3 years ago

What is the mass of the other block?

xeze [42]

Let us consider the tension produced on both the sides of the rope is T.

We have been given that the rope is mass less and the rope is passing through a pulley which is stationary.

$Let\ m_{1} and\ m_{2}\ are\ the\ masses\ of\ two\ blocks$

$Let\ m_{1}\ is\ moving\ in\ vertical\ upward\ direction\ while\ m_{2}\ is\ in\ downward\ \ direction$

$Hence\ m_{2} =4.5\ kg$

The body is moving downward with an acceleration of $\frac{3}{4} g$

As the rope is the same one which is passing over a mass less pulley and connected by two masses,hence, acceleration of each block will be the same in magnitude.

$For\ body\ m_{1}$

Here the tension is acting in vertical upward direction and the weight is acting in vertical downward direction. Here,the body is moving in vertical upward direction. Hence, the net force acting on it is-

$T-m_{1} g=m_{1}a$ [1]

$For\ body\ m_{2}$

Here the tension is acting in vertical upward direction while weight is in vertical downward direction. The body is moving in downward direction. Hence the net force acting on it will be-

$m_{2} g-T=m_{2} a$ [2]