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lesya [120]
3 years ago
5

A volume of 25 milliliters is the same as a volume of ____________________ cubic centimeters.

Physics
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

25 cm³

Explanation:

In the conversion of units, we know that are one cubic centimeters (cm³) in a milliliter (mL) .

1 milliliter = 1 cubic centimeter

25 milliliters = 25 cubic centimeters

Therefore, a volume of 25 milliliters is the same as a volume of 25 cubic centimeters.

This ultimately implies that, the volume of an object in milliliters is equivalent to its volume in cubic centimeters.

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1. Is the image projected on a movie screen real or virtual? What about the image of yourself seen in a bathroom mirror?
antiseptic1488 [7]

Answer: 1. The movie one is virtual and the bathroom mirror is real

2. The image is distorted in a way

3. Behind the spoon

Explanation:

7 0
2 years ago
Melanie gets out of her car at the park. She walks 25 m to the trail entrance.
zhenek [66]

The reference point that should be used to describe Melanie motion is the pond (option C).

<h3>What is reference point?</h3>

Reference point is a particular point in space which is used as an endpoint to measure a distance from or chart a map from.

According to this question, Melanie gets out of her car at the park and walks 25 m to the trail entrance. She jogs around the trail until she reaches a pond, where she stops briefly.

However, she then continues to follow the trail around the pond. This suggests that the pond should serve as the reference point for Melanie's motion.

Learn more about reference point at: brainly.com/question/14318992

#SPJ1

3 0
2 years ago
1500 kg Peugeot car is traveling at 16.67 m s ⁻¹ and accelerates to 30.56 m s ⁻¹ for 2 minutes. Calculate the impulse of the car
Elis [28]

Answer:

2084 kg*m/s

Explanation:

Impulse is change in momentum

Mathematically;

Impulse, J= F*t=mΔv   where

F= ma = 1500 * { 30.56 - 16.67}/2*60

F= 1500 *0.11575

F=  174 N

J=F*t

J= 174*120*0.1

J= 2084 kg*m/s

5 0
2 years ago
Suppose a ceiling fan has a mass of 7.5 kg and is 9.7 m above the ground. What is the gravitational potential energy of the ceil
EleoNora [17]

The gravitational potential energy (G.P.E) of the ceiling fan is 712.95 Joules.

<u>Given the following data:</u>

  • Mass of ceiling fan = 7.5 kg
  • Height = 0.7 m

<u>Scientific data:</u>

  • Acceleration due to gravity = 9.8 m/s^2

To calculate the gravitational potential energy (G.P.E) of the ceiling fan:

<h3>What is gravitational potential energy?</h3>

Gravitational potential energy (G.P.E) can be defined as the energy that is possessed by an object or body due to its position (height) above planet Earth.

Mathematically, gravitational potential energy (G.P.E) is given by this formula;

GPE = mgh

<u>Where:</u>

  • G.P.E is the gravitational potential energy.
  • m is the mass of an object.
  • g is the acceleration due to gravity.
  • h is the height of an object.

Substituting the given parameters into the formula, we have;

GPE = 7.5 \times 9.8 \times 9.7

GPE = 712.95 Joules.

Read more on potential energy here: brainly.com/question/8664733

8 0
2 years ago
The route followed by a hiker consists of three displacement vectors, X, Y and Z. Vector X is along a measured trail and is 1430
poizon [28]

Answer:

  • magnitude : 1635.43 m
  • Angle: 130°28'20'' north of east

Explanation:

First, we will find the Cartesian Representation of the \vec{X} and \vec{Y} vectors. We can do this, using the formula

\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | its the magnitude of the vector and θ the angle. For  \vec{X} we have:

\vec{X}= 1430 m \ ( \ cos( 42 \°) \ , \ sin (42 \°) \ )

\vec{X}= ( \ 1062.70 m \ , \ 956.86 m \ )

where the unit vector \hat{i} points east, and \hat{j} points north. Now, the \vec{Y} will be:

\vec{Y}= - 2200 m \hat{j} = ( \ 0 \ , \ - 2200 m \ )

Now, taking the sum:

\vec{X} + \vec{Y} + \vec{Z} = 0

This is

\vec{Z} = - \vec{X} - \vec{Y}

(Z_x , Z_y) = - ( \ 1062.70 m \ , \ 956.86 m \ ) - ( \ 0 \ , \ - 2200 m \ )

(Z_x , Z_y) = ( \ - 1062.70 m \ ,  \ 2200 m \ - \ 956.86 m \ )

(Z_x , Z_y) = ( \ - 1062.70 m \ ,  \ 1243.14 m\ )

Now, for the magnitude, we just have to take its length:

|\vec{Z}| = \sqrt{Z_x^2 + Z_y^2}

|\vec{Z}| = \sqrt{(- 1062.70 m)^2 + (1243.14 m)^2}

|\vec{Z}| = 1635.43 m

For its angle, as the vector lays in the second quadrant, we can use:

\theta = 180\° - arctan(\frac{1243.14 m}{ - 1062.70 m})

\theta = 180\° - arctan( -1.1720)

\theta = 180\° - 45\°31'40''

\theta = 130\°28'20''

5 0
3 years ago
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