The acceleration of the particle as a function of time t is

The velocity of the particle at time t is the integral of the acceleration:

where the constant C can be found by requiring that the velocity at time t=0 is v=3:

and we find

so the velocity is

The position of the particle at time t is the integral of the velocity:

where D can be found by requiring that the initial position at time t=0 is zero:
x(0)=0
from which we find D=0, so
To solve the problem, now we just have to substitute t=5 into x(t) and v(t) to find the position and the velocity of the particle at t=5.
The position is:

and the velocity is:
The answer of this is C!!!
Answer:
you may get bullied or teased for being a differrent race, ethnic.
Answer
given,
Side of copper plate, L = 55 cm
Electric field, E = 82 kN/C
a) Charge density,σ = ?
using expression of charge density
σ = E x ε₀
ε₀ is Permittivity of free space = 8.85 x 10⁻¹² C²/Nm²
now,
σ = 82 x 10³ x 8.85 x 10⁻¹²
σ = 725.7 x 10⁻⁹ C/m²
σ = 725.7 nC/m²
change density on the plates are 725.7 nC/m² and -725.7 nC/m²
b) Total change on each faces
Q = σ A
Q = 725.7 x 10⁻⁹ x 0.55²
Q = 219.52 nC
Hence, charges on the faces of the plate are 219.52 nC and -219.52 nC