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Ivenika [448]
3 years ago
9

Which of the following are signs of a chemical change/reaction? Select all that apply.

Chemistry
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

the answers are

Explanation:

5,6,7,8&9.

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A statement that best describes a solution
PIT_PIT [208]
A solution is usualy a diluted liquid that cleans for example bleach solution.
6 0
3 years ago
What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?
charle [14.2K]

Answer:

The correct answer is 187.7 J/Jg.

Explanation:

The formula for finding the specific heat of fusion is,  

Specific heat of fusion = Q/m

Here Q is the heat energy added, signified in kJ, and m is the mass of the object in kg.  

Based on the given information, the heat energy added or Q is 869 kJ and the mass of the ice is 4.6 Kg

Now putting the values in the formula we get,  

Specific heat of fusion = Q/m

Specific heat of fusion = 863 kJ / 4.6 Kg = 187.7 J/Kg

5 0
3 years ago
What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?
Westkost [7]
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



6 0
3 years ago
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
A measure of the kinetic energy of particle motion within a substance is temperature.
Natali5045456 [20]
I believe it’s true when particles move they create heat
4 0
3 years ago
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