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STatiana [176]
4 years ago
10

The number of atoms of sulfur in 2.66 grams of sulfur

Chemistry
1 answer:
Sedbober [7]4 years ago
5 0
<h3>Answer:</h3>

5.0 × 10^21 atoms of sulfur

<h3>Explanation:</h3>

We need to know that 1 mole of an element contains atoms equivalent to the Avogadro's number.

Therefore;

1 mole of an element = 6.022 × 10^23 atoms

Thus, 1 mole of sulfur = 6.022 × 10^23 atoms

But, molar mass of sulfur = 32.065 g/mol

This means;

32.065 g contain 6.022 × 10^23 atoms

Therefore, 2.66 g of Sulfur will contain;

= (2.66 g ÷ 32.065 g/mol) ×  6.022 × 10^23 atoms

= 5.0 × 10^21 atoms

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3 years ago
In the chemical reaction below, calcium (Ca) and water (H2O) react to form calcium hydroxide (Ca(OH)2) and hydrogen gas (H2). Ca
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C.

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. What is the molarity of a solution that was prepared by dissolving 80.0 g of CaCl2 (molar mass = 111.1 g/mol) in enough water
garri49 [273]

Explanation:

Molarity = mol/L or g/L

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Mass>80.0g

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V>500mL

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x=500mL. =0.720072007mol

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