Answer:
1) Moles of CO 2 = Given mass / Molecular mass of CO 2 = 4.4 / 44 = 0.1 mole. 2) Molecules of CO2 in 0.1 moles of CO2 = 0.1 x 6.023 x 10 23 = 6.023 x 10 22 molecules 3) 44 gram (molecular wt of CO 2) contains 2 moles atom of oxygen therefore 4.4 gram of CO2 will contain = 2 /44 *4.4 = 0.2 moles atom of Oxygen.
Organic molecule. In particular, a carbohydrate.
Answer:
Explanation:
I dont know please tell me
Answer:
44.6millilitres
Explanation:
Using the general gas law equation as follows:
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
V1 = initial volume (L)
T1 = initial temperature (K)
P2 = final pressure (atm)
V2 = final volume (L)
T2 = final temperature (K)
According to this question;
V1 = 30mL
T1 = 273K (STP)
P1 = 1 atm (STP)
V2 = ?
T2 = 300K
P2 = 75.0 kPa = 75 × 0.00987 = 0.74atm
Using P1V1/T1 = P2V2/T2
1 × 30/273 = 0.74×V2/300
30/273 = 0.74V2/300
Cross multiply
300 × 30 = 273 × 0.74V2
9000 = 202.02V2
V2 = 9000/202.02
V2 = 44.55
V2 = 44.6millilitres.
