All categories

4 years ago

Why bucket of water is filled faster in downstairs tap than in the upstairs tap

Physics

1 answer:

Lapatulllka [165]4 years ago

6 0

I think that the downstairs would be faster because the water wouldn't have to go all the way up which make it slower

You might be interested in

A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from x = −

romanna [79]

Answer:

The speed of electron is $1.5\times10^{7}\ m/s$

Explanation:

Given that,

Electric field $E=1.50\times10^{3}\ N/C$

Distance = -0.0200

The electron's speed has fallen by half when it reaches x = 0.190 m.

Potential energy $P.E=5.04\times10^{-17}\ J$

Change in potential energy $\Delta P.E=-9.60\times10^{-17}\ J$ as it goes x = 0.190 m to x = -0.210 m

We need to calculate the work done by the electric field

Using formula of work done

$W=-eE\Delta x$

Put the value into the formula

$W=-1.6\times10^{-19}\times1.50\times10^{3}\times(0.190-(-0.0200))$

$W=-5.04\times10^{-17}\ J$

We need to calculate the initial velocity

Using change in kinetic energy,

$\Delta K.E = \dfrac{1}{2}m(\dfrac{v}{2})^2+\dfrac{1}{2}mv^2$

$\Delta K.E=\dfrac{-3mv^2}{8}$

Now, using work energy theorem

$\Delta K.E=W$

$\Delta K.E=\Delta U$

So, $\Delta U=W$

Put the value in the equation

$\dfrac{-3mv^2}{8}=-5.04\times10^{-17}$

$v^2=\dfrac{8\times(5.04\times10^{-17})}{3m}$

Put the value of m

$v=\sqrt{\dfrac{8\times(5.04\times10^{-17})}{3\times9.1\times10^{-31}}}$

$v=1.21\times10^{7}\ m/s$

We need to calculate the change in potential energy

Using given potential energy

$\Delta U=-9.60\times10^{-17}-(-5.04\times10^{-17})$

$\Delta U=-4.56\times10^{-17}\ J$

We need to calculate the speed of electron

Using change in energy

$\Delta U=-W=-\Delta K.E$

$\Delta K.E=\Delta U$

$\dfrac{1}{2}m(v_{f}^2-v_{i}^2)=4.56\times10^{-17}$

Put the value into the formula

$v_{f}=\sqrt{\dfrac{2\times4.56\times10^{-17}}{9.1\times10^{-31}}+(1.21\times10^{7})^2}$

$v_{f}=1.5\times10^{7}\ m/s$

Hence, The speed of electron is $1.5\times10^{7}\ m/s$

4 0

3 years ago

¿Qué significa que un automóvil viaje con una rapidez de 45[(Km.)⁄(Hr.)]?

netineya [11]

Responder:

Compruebe amablemente la explicación

Explicación:

¿Qué significa que un automóvil viaje con una rapidez de 45 [(Km.) ⁄ (Hr.)]?

Si se dice que un automóvil viaja a una velocidad de 45 km / h, entonces el automóvil cubre una distancia de 45 km en una hora. 45 km / h es una derivación de la velocidad de desplazamiento obtenida de la relación;

Velocidad = distancia / tiempo

Velocidad = 45 km / 1 h.

Distancia = velocidad × tiempo

Distancia = 45 km / h × 1 h

Distancia = 45 km

Por lo tanto, a esa velocidad, se cubrirá una distancia de 45 km por cada hora que se mueva.

4 0

3 years ago

What is the characteristics of sound

tankabanditka [31]

Answer:

Sound wave can be described by five characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed.

5 0

3 years ago

Read 2 more answers

The cheetah can reach a top speed of 114 km/h (71 mi/h). While chasing its prey in a short sprint, a cheetah starts from rest an

Mariulka [41]

Answer: a= 4.4ms-2

Displacement= 26.95 m

Explanation:

First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.

7 0

4 years ago

Read 2 more answers

A star rotates with a period of 37 days about an axis through its center. The period is the time interval required for a point o

vlabodo [156]

Answer:

T = 1.1285 10⁻² day

Explanation:

For this exercise the forces in the premiere are internal, so the angular momentum is conserved

L₀ = I₀ w₀

L = I w

L₀ = L

I₀ w₀ = I w

Angular velocity and period are related

w₀ = 2π / T₀

w = 2π / T

The moment of inertia of a sphere is

I₀ = 2/5 M R²

I = 2/5 m r²

If we assume that the mass of the star does not change in the transformation

We substitute

2/5 M R² 2π/T₀ = 2/5 M r² 2π/ T

R² /T₀ = r² / T

T = (r / R)² T₀

T = (6.1 / 2.0 104) 37

T = 1.1285 10⁻² day

5 0

3 years ago