Answer:
Current, I = 3.57A
Explanation:
A current of I amperes means that I Coulombs of charge flows through the conductor (heating coil) per second.
Therefore, in time t, the total charge (Q) passing through any point in which the current (C) flows will be given by the equation;
Q = It
Where; Q is the charge in coulombs; I is the current in amperes; t is the time in seconds.
From the question, we were given the following parameters;
Q = 25C, t= 7secs and I =?
From the equation, Q = It
We make current, I the subject of formula;
Thus, I = Q/t
Substituting into the equation;
I = 25/7
I = 3.57Amp.
Answer:
Explanation:
Theoretical efficiency = T₁ - T₂ / T₁ where T₁ and T₂ is absolute temperature of hot and cold end of the heat engine.
= 600 / (273 + 700 )
= 600 / 973
= .6166
operating efficiency = 40% of .6166
= .4 x .6166
= .2466 = 24.66 %
efficiency = work output / heat input
= 5000 / heat input = .2466
heat input = 5000 / .2466
= 20275.75 J .
HEAT EXTRACED = 20275.75 J.
Answer:
number 10 is the value of acceleration due to gravity.
Answer:
Δp = 0.05 p
Explanation:
The moment is
p = m v
The uncertainty of the moment is
Δp = dp/dm Δm + dp/dv Δv
Like the uncertainty in the mass is zero
Δm = 0
ΔP = m Δv
We divide for the moment
Δp / p = Δv / v
They do not indicate that Δv / v = 0.05
Δp / p = 0.05
Δp = 0.05 p
In the case of a system consisting of two cars
p = m₁ v₁ + m₂ v₂
Δp = dp / dv₁ Δv₁ + dp / dv₂ Δv₂
Δp = m₁ Δv₁ + m₂ Δv₂
Δv₁ / v₁ = 0.05
Δv₁ = 0.05 v₁
Δv₂ / v₂ = 0.05
Δv₂ = 0.05 v₂
We replace
Δp = m₁ 0.05 v₁ + m₂ 0.05 v₂
Δp = 0.05 p
