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Genrish500 [490]
4 years ago
10

If the Sun suddenly turned off, we would not know it until its light stopped coming. How long would that be, given that the Sun

is 1.50x10'' m away?
Physics
1 answer:
Yuliya22 [10]4 years ago
3 0

Answer:

8.33 minutes

Explanation:

First let us find out how much time it takes for the light for the sun to reach the earth

Distance between Earth and Sun is 1.5×10¹¹ m

Speed of light = 3×10⁸ m/s

\text{Time taken}=\frac{1.5\times 10^{11}}{3\times 10^8}\\\Rightarrow \text{Time taken}=500\ seconds

Converting to minutes

500\ seconds=\frac{500}{60}=8.33\ minutes

So, it takes 8.33 minutes for the light from the sun to reach Earth.

This means that we would be receiving light for 8.33 minutes after the Sun turned off.

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As altitude increases, air pressure ____.
MAVERICK [17]

Answer:

decreases

Explanation:

Decreases

5 0
4 years ago
If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular co
MissTica

Answer:

35.36776 Hz

Explanation:

B = Magnetic field = 9\times 10^{-3}}\ T

E_m = Maximum voltage = 20 V

d = Diameter of coil = 40 cm = 0.4 m

A = Area = \pi \frac{d}{2}^2=\pi 0.2^2

N = Number of turns = 500

\omega = Angular velocity

Maximum emf is given by

E_m=NAB\omega\\\Rightarrow \omega=\frac{E_m}{NAB}\\\Rightarrow \omega=\frac{20}{500\times \pi\times 0.2^2\times 9\times 10^{-3}}\\\Rightarrow \omega=35.36776\ Hz

The angular velocity would be 35.36776 Hz

8 0
4 years ago
Chich expression correctly describes force using Sl units
Zinaida [17]

Answer:1 N = 1 kg·m/s2

Explanation:

5 0
3 years ago
Question 1<br> 2 pts<br> Explain what causes a solution to be a strong acid.
lubasha [3.4K]

Answer:

Cuanto más fuerte es el ácido, más rápido se disocia para generar H +start superscript, plus, end superscript. Por ejemplo, el ácido clorhídrico (HCl) se disocia completamente en iones hidrógeno y cloruro cuando se mezcla con agua, por lo que se considera un ácido fuerte.

5 0
3 years ago
An energy plant produces an output potential of 1500 kV and serves a city 143 km away. A high-voltage transmission line carries
jekas [21]

Answer:

2123.55 $/hr

Explanation:

Given parameters are:

V_{plant} = 1500 KV

L = 143 km

I = 500 A

\rho = 2.4 \Omega / km

So, we will find the voltage potential provided for the city as:

V_{wire} =IR = I\rho L = 1500*2.4*143 = 514.8 kV

V_{city} = V_{plant}- V_{wire} = 1500-514.8 = 985.2 kV

Then, we will find dissipated power because of the resistive loss on the transmission line as:

P = I^2R = I^2\rho L=500^2*2.4*143 = 8.58*10^7 W

Since the charge of plant is not given for electric energy, let's assume it randomly as x =  \frac{\dollar 0.081}{kW.hr}

Then, we will find the price of energy transmitted to the city as:

Cost = P * x = 8.58*10^7 * 0.081 * 0.001 = 6949.8 $/hr

To calculate money per hour saved by increasing the electric potential of the power plant:

Finally,

I_{new} = P/V_{new} = I/1.2\\P_{new} = I_{new}^2R_{wire}\\Cost = P_{new}/1.44=6949.8/1.44 = 4826.25 $/hr

The amount of money saved per hour = 6949.8 - 6949.8/1.44 = 2123.55 $/hr

Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.

3 0
3 years ago
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