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Oduvanchick [21]
3 years ago
12

You have two contentious friends, Chris and Pat, and you’ve quickly discovered that they need you to resolve arguments they have

about physics concepts. Chris says, "The spacing between two dots tells you the speed at the time of the first dot," but Pat says, "The spacing tells you the speed at the time of the second dot. How do you resolve this debate?"
Physics
1 answer:
pshichka [43]3 years ago
3 0

Answer:

v_average = (d₂-d₁) / Δt

this average velocity is not necessarily the velocity of the extreme points,

Explanation:

To resolve the debate, it must be shown that the two have part of the reason, the space or distance between the two points divided by time is the average speed between the points.

             v_average = (d₂-d₁) / Δt

this average velocity is not necessarily the velocity of the extreme points, in the only case that it is so is when there is no acceleration.

Therefore neither of them is right.

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All you have to do is multiply that by the mass or volume.
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In its search for flying insects, a bat uses an echolocating system based on pulses of high frequency sound. These pulses are 2.
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The amount of energy that a wave may transfer to a unit area of a surface each second is measured as the wave's intensity. Watts per square meter is a unit used to express intensity. A sound wave's frequency is equal to its rate of vibration, and its intensity is determined by its amplitude.

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The energy of a vibration is quantified in decibels as intensity or loudness (dB). A sound has a high intensity if it is loud.

Therefore, perceive noise as louder the higher the frequency, although frequency does not indicate how loud a sound is.

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4 0
1 year ago
Two capacitors with capacitances of 1.0 m F and 0.50 m F, respectively, are connected in series. The system is connected to a 10
forsale [732]

Answer:

Therefore energy is stored in the 1.0 mF capacitor is 5.56×10⁻⁹ J

Explanation:

Series capacitor: The ending point of a capacitor is the starting point of other capacitor.

If C₁ and C₂ are connected in series then the equivalent  capacitance is C.

where     \frac{1}{C} =\frac{1}{C_1}+\frac{1}{C_2}

Given that,

C₁ = 1.0 mF=1.0×10⁻³F  and  C₂ = 0.50mF=0.50×10⁻³F  

If C is equivalent capacitance.

Then    \frac{1}{C} =\frac{1}{1.0}+\frac{1}{0.5}

\Rightarrow \frac{1}{C} =\frac{3}{1}

\Rightarrow C=\frac{1}{3} mF

Again given that the system is connected to a 100-v battery.

We know that

q=Cv

q= charge

C= capacitor

v= potential difference

Therefore

q=(\frac{1}{3} \times 10^{-3}\times10) C

 =\frac{10^{-2}}{3} C

The electrical potential energy stored in a capacitor can be expressed

U=\frac{q^2C}{2}

q= charge

c=capacitance of a capacitor

Therefore energy is stored in the 1.0 mF capacitor is

U=\frac{q^2C_1}{2}

\Rightarrow U=\frac{(\frac{10^{-2}}{3})^2\times 10^{-3} }{2}

\Rightarrow U= 5.56\times 10^{-9} J

 

8 0
3 years ago
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Ipatiy [6.2K]
Weight changes due to the gravitational pull in mars,basically gravity
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4 years ago
Problem 7.17 A horizontal spring with stiffness 0.8 N/m has a relaxed length of 12 cm (0.12 m). A mass of 23 grams (0.023 kg) is
Jlenok [28]

The speed of the mass v = 0.884 m/s.

<u>Explanation</u>:

Let

K1 represents the kinetic energy of the mass when it is released,

U1 represents the potential energy of the spring when the mass is released,

K2 represents the kinetic energy of the mass when the spring returns to relaxed length,

U2 represents the potential energy of the spring when the spring returns to relaxed length

The spring is stretched by 0.27 - 0.12 = 0.15 m

                                K1 = 0

                                 U1 = (1/2) \times 0.8 \times (0.15)^2

                                     = 0.009 J

                                U2 = 0

By conservation of energy,

                        K2 + U2 = K1 + U1

                           K2 + 0 = 0 + 0.009 J

                                 K2 = 0.009 J

Let v = speed of the mass

                                K2 = 1/2 \times m \times v^2

m = 23 g = 0.023 kg

                           0.009 = 1/2 \times 0.023 \times v^2

                           0.009 = 0.0115 \times v^2

                                   v = √(0.009 / 0.0115)

                                  v = 0.884 m/s.

5 0
4 years ago
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