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2 years ago

1. A 1000 kg equipment lift travels up a 200 m shaft in 45 seconds. Assuming the speed is constant, what is the

Physics

1 answer:

ANTONII [103]2 years ago

8 0

Answer:

43,555 W

Explanation:

Since the speed is constant, this means that the force applied to lift the equipment is equal to the weight of the equipment. So we can write:

$F=mg$

where

m = 1000 kg is the mass

$g=9.8 m/s^2$ is the acceleration due to gravity

So,

$F=(1000)(9.8)=9800 N$

Then the work done in lifting the equipment is:

$W=Fd$

where

d = 200 m is the displacement of the equpment

Substituting,

$W=(9800)(200)=1.96\cdot 10^6 J$

Finally, the power used to lift the equipment is the ratio between the work done and time taken:

$P=\frac{W}{t}$

where

$W=1.96\cdot 10^6 J$

t = 45 s is the time taken

Solving,

$P=\frac{1.96\cdot 10^6}{45}=43,555 W$

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2 years ago

A friend tells you that a lunar eclipse will take place the following week, and invites you to join him to observe the eclipse t

WARRIOR [948]

Answer:

y = 80.2 mille

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3 years ago

A 35 kg box rests on the back of a truck. The coefficient of static friction bet?005 (part 1 of 2)A 35 kg box rests on the back

elena-14-01-66 [18.8K]

Answer with Explanation:

We are given that

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Coefficient of static friction between box and truck bed=0.202

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3 years ago

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