Describe how you can use tempenture to compare how much thermal energy two objects have

FIRST ANSWER GETS BRAINLIST:

bezimeni [28]

Object A and Object B...

8 0

3 years ago

Read 2 more answers

Need help ASAP

vlada-n [284]

(1) The parallel force on the Jumper is 441.42 N.

(2) The weight of the person is heavier on Earth when compared to Mars by 610 N.

<h3>Parallel force on the Jumper</h3>

The parallel force on the Jumper is determined from the parallel components of the weight of the jumper.

F = W x sinθ

F = (85 x 9.8) x sin32

F = 441.42 N

<h3>Weight of the person on Earth</h3>

W = mg

W = 100 x 9.8

W = 980 N

<h3>Weight of the person on Mars</h3>

W = mg

W = 100 x 3.7

W = 370 N

<h3>Difference between the weights</h3>

= 980 N - 370 N

= 610 N

Thus, the weight of the person is heavier on Earth when compared to Mars by 610 N.

Learn more about weight here: brainly.com/question/2337612

#SPJ1

4 0

2 years ago

A 30000 grams boy is riding a merry-go-round with a radius of 600 cm. What is the centripetal force and acceleration on the boy

irga5000 [103]

Answer:

centripetal force is calculated by mass(kg) × tangetial velocity(m/s) ÷ radius (m)

Explanation:

so 30000g= 30kg

50km/h = 13.88m/s

600cm= 6m

30×13.88÷6= 69.4N

N= Newton's

hope this helps.

btw I'm 16 and love physics so I tried my best in this hope it went well!!

7 0

3 years ago

A driver enters a one-lane tunnel at 34.4 m/s. The driver then observes a slow-moving van 154 m ahead travelling (in the same di

navik [9.2K]

Answer:

Ans. B) 22 m/s (the closest to what I have which was 20.16 m/s)

Explanation:

Hi, well, first, we have to find the equations for both, the driver and the van. The first one is moving with constant acceleration (a=-2m/s^2) and the van has no acceletation. Let´s write down both formulas so we can solve this problem.

$X(van)=5.65t+154$

$X(driver)=34.4t+\frac{(-2)t^{2} }{2}$

or by rearanging the drivers equation.

$X(driver)=34.4t+t^{2}$

Now that we have this, let´s equal both equations so we can tell the moment in which both cars crashed.

$X(van)=X(driver)$

$5.65t+154=34.4t-t^{2}$

$0=t^{2} -(34.4-5.65)t+154$ $0=t^{2} -28.75t+154$

To solve this equation we use the following formulas

$t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}$

Where a=1; b=-28.75; c=154

So we get:

$t=\frac{28.75 +\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=21.63s$ $t=\frac{28.75 -\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=7.12s$

At this point, both answers could seem possible, but let´s find the speed of the driver and see if one of them seems ilogic.

$V(driver)=V_{0} +at$ }

$V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(7.12s)=20.16\frac{m}{s}$ $V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(21.63s)=-8.86\frac{m}{s}$

This means that 21.63s will outcome into a negative speed, for that reason we will not use the value of 21.63s, we use 7.12s and if so, the speed of the driver when he/she hits the van is 20.16m/s, which is closer to answer A).

Best of luck

8 0

3 years ago

A 790N person runs up a flight of 40 stairs (.25m for each step) in 20 seconds, and then down 10 steps in 5 seconds. How much to

Romashka [77]

A person runs up 40 stairs and then come down 10 steps

So total stairs upwards is given as

$N = 40 - 10 = 30$