Question

Suri rolled a bowling ball down a lane in 2.5 s. The ball traveled

Answer 1

Answer:

3.1 m/s

Explanation:

The acceleration of the ball is given by:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time elapsed

Here we know:

a = 1.8 m/s^2 is the acceleration

v = 7.6 m/s is the final velocity

t = 2.5 is the time elapsed

Solving for u, we find the initial velocity of the ball:

$u=v-at=7.6 m/s-(1.8 m/s^2)(2.5 s)=3.1 m/s$