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madam [21]
3 years ago
11

What energy transformation takes place in the solar panel?

Physics
1 answer:
aliina [53]3 years ago
3 0
I think it’s the first option
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A student pulls a 50-newton sled with a force having a magnitude of 15 newtons. What is the magnitude of the force that the sled
Simora [160]

Answer:

Force = 35 N

Explanation:

From Newton's third law of motion, the boy must apply a force greater than the weight of the sled to lift it.

weight of sled = mg

where m is its mass and g the force of gravity on it.

weight of sled = 50 N

Force applied by the boy on the sled = 15 N

Since the force applied on the sled by the boy is lesser than the weight of the sled, then;

Force that the sled exerts on the student = 50 - 15

                                             = 35 N

The force exerted by the sled on the student is 35 N.

5 0
3 years ago
Stars are held together by the force ___, ___ and the composition determine the amount of ___.
Alexus [3.1K]
A star is a large ball of gas that generates its own energy by fusing hydrogen atoms to make helium. It is held together by its own gravity. ... Stars come in a variety of sizes and compositions, which determine their amount of energy and gravity.
4 0
3 years ago
1.1
podryga [215]

  • Biosphere: The living spaces of living and non-living things are called habitats.
  • Ecosystem: They are natural areas where living and non-living interactions occur.
  • Hydrosphere: Water is sphere. It is the layer formed by water bodies such as oceans and seas in the world.
  • Lithosphere: It is a stone sphere. It is the layer formed by rock and terrestrial regions in the world.
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7 0
3 years ago
At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constan
oksian1 [2.3K]

Answer:

(A) Distance taken by automobile to overtake truck is 175.23 m

(B) Final speed of the automobile is 29.6 m/s.

Explanation:

According to the problem, the automobile is at rest, so its initial speed is zero and the automobile is moving with constant acceleration.

The general equation of motion is:

d = ut + 0.5at²      .....(1)

Here d is distance, a is acceleration, t is time and u is initial speed.

The distance (d₁) travel by the automobile after green light in time t is given by the relation :

d₁ = u₁t + 0.5at²

We know that its initial velocity is zero i.e. u = 0 m/s.

d₁ = 0.5at²      ......(2)

The truck is moving with constant speed, so its acceleration is zero. Therefore, the distance covered by the truck using equation (1) is;

d₂ = u₂t         .......(3)

Since, the distance travelled by automobile and truck are same. Hence,

d₁ = d₂

0.5at² = u₂t

t = 2u₂/a

Substitute 14.8 m/s for u₂ and 2.50 m/s² for a in the above equation.

t = \frac{2\times14.8}{2.50}

t = 11.84 s

(A) Distance travelled by automobile, d = u₂t =14.8 x 11.84 = 175.23 m

(B) Final speed of the automobile is given by the relation:

v = u + at

v = 0 + 2.50 x 11.84

v = 29.6 m/s

4 0
3 years ago
A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.400 rev
saw5 [17]

Answer:

The final angular velocity is rev/s is 0.293 rev/s.

Explanation:

Given;

mass of the merry-go-round, m₁ = 120 kg

radius of the merry-go-round, r = 1.8 m

initial angular velocity, ω = 0.4 rev/s

mass of the child, m₂ = 22 kg

Apply the principle of conservation angular momentum to determine the final angular velocity;

I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2  + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2  + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1  + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\

Therefore, the final angular velocity is rev/s is 0.293 rev/s.

3 0
3 years ago
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