Ask question

Ask question

All categories

3 years ago

11

When approaching a vehicle that does not dim their headlights you can: blink your high beams once leave on your high beams until

they adjust their headlights stay to the center yellow line?

1 answer:

Margaret [11]3 years ago

7 0

If an oncomimg car has high beams on and doesn't dim them, blink your highbeams once to signal them to turn their highbeams off.

You might be interested in

A uniform solid cylinder with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with an angular speed of 33.4

DENIUS [597]

Answer:

Is the equation for Ec=1/2 m(Dv)^2 where Dv is the difference between the angular speed & the areolar speed?

5 0

4 years ago

Explain the types of root

Alex_Xolod [135]

Answer:

there are two main type of root systems.

6 0

3 years ago

Read 2 more answers

How does the direction of current flow in the coil affect the orientation of the magnetic field produced by the electromagnet

Lynna [10]

Answer:

The magnetic field produced by an electric current is always oriented perpendicular to the direction of the current flow. And.Direction of magnetic field is governed by the 'right hand thumb rule, The right hand rule states that: to determine the direction of the magnetic force on a positive moving charge, ƒ, point the thumb of the right hand in the direction of v, the fingers in the direction of B, and a perpendicular to the palm points in the direction of Force . Similar to the situation with electric field lines, the greater the number of lines (or the closer they are together) in an area the stronger the magnetic field.

8 0

3 years ago

A car moving with an initial speed of 25 m/s slows down to a speed of 5 m/s in 10 seconds Calculate a) the acceleration of the c

stealth61 [152]

Answer :

(a) The acceleration of the car is, $-2m/s^2$

(b) The distance covered by the car is, 150 m

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 5 m/s

u = initial velocity = 25 m/s

t = time = 10 s

a = acceleration of the car = ?

Now put all the given values in the above equation 1, we get:

$5m/s=25m/s+a\times (10s)$

$a=-2m/s^2$

The acceleration of the car is, $-2m/s^2$

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$ ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity = 25 m/s

t = time = 10 s

a = acceleration of the car = $-2m/s^2$

Now put all the given values in the above equation 2, we get:

$s=(25m/s)\times (10s)+\frac{1}{2}\times (-2m/s^2)\times (10s)^2$

By solving the term, we get:

$s=150m$

The distance covered by the car is, 150 m

8 0

3 years ago

How much heat is required to convert 10.0 g of ice at -14.0 ∘c to steam at 100.0 ∘c?

sdas [7]

What do you think? how long does your hand touch fire until it feels heat.

4 0

3 years ago