the minimum frequency of radiation that will produce a photoelectric effect
<h2>#CarryOnLearning</h2>
Answer:
It just means that you are supposed to find an object that is not used in a vacuum. For example, a hair-brush is not use in a vacuum lol
When a solution of MgCl₂ and a solution of AgNO₃ are mixed, the net ionic equation obtained is:
2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)
<h3>What is a chemical equation? </h3>
Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.
The reactants are located on the left side while the products are located on the right side.
Reactants —> Products
The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
<h3>How to write the net ionic equation </h3>
In solution
MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)
AgNO₃(aq) —> Ag⁺(aq) + NO₃¯(aq)
The reaction proceeds as follow
MgCl₂(aq) + AgNO₃(aq) —>
Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) —> 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)
Cancel out the spectator ions (i.e Mg²⁺ and NO₃¯) to obtain the net ionic equation
2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)
Learn more about chemical equation:
brainly.com/question/7181548
Answer:
a.
![Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BHCO_3%5E-%5D%5BOH%5E-%5D%7D%7B%5BCO_3%5E%7B2-%7D%5D%7D)
b.
![Keq=[O_2]^3](https://tex.z-dn.net/?f=Keq%3D%5BO_2%5D%5E3)
c.
![Keq=\frac{[H_3O^+][F^-]}{[HF]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BF%5E-%5D%7D%7B%5BHF%5D%7D)
d.
![Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BNH_4%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BNH_3%5D%7D)
Explanation:
Hello there!
In this case, for the attached reactions, it turns out possible for us to write the equilibrium expressions by knowing any liquid or solid would be not-included in the equilibrium expression as shown below, with the general form products/reactants:
a.
![Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BHCO_3%5E-%5D%5BOH%5E-%5D%7D%7B%5BCO_3%5E%7B2-%7D%5D%7D)
b.
![Keq=[O_2]^3](https://tex.z-dn.net/?f=Keq%3D%5BO_2%5D%5E3)
c.
![Keq=\frac{[H_3O^+][F^-]}{[HF]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BF%5E-%5D%7D%7B%5BHF%5D%7D)
d.
![Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BNH_4%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BNH_3%5D%7D)
Regards!
Answer: Theoretical yield of
produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
![\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20solute%7D%3D%5Cfrac%7B%5Ctext%7Bgiven%20mass%7D%7D%7B%5Ctext%7BMolar%20Mass%7D%7D)
![\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7D%20S%3D%5Cfrac%7B8.96g%7D%7B32g%2Fmol%7D%3D0.28moles)
The balanced chemical equation is:
According to stoichiometry :
2 moles of
produce = 3 moles of ![SO_3](https://tex.z-dn.net/?f=SO_3)
Thus 0.28 moles of
will produce=
of
Mass of ![SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g](https://tex.z-dn.net/?f=SO_3%3Dmoles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D0.42moles%5Ctimes%2080g%2Fmol%3D33.6g)
Thus theoretical yield of
produced by 8.96 g of S is 33.6 g