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faust18 [17]
3 years ago
12

Nitrogen family - 5 valence electrons

Chemistry
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

  • <u>The elements that belong to the nitrogen family are nitrogen, phosphorus, arsenic, antimonium, bismuth, and moscovium.</u>

Explanation:

<em>Families</em> are group of elements that belong to the same column in the periodic table.

Some families have a well known name. For instance, alkali metals is the family of the elements that belong to the first column: Li, Na, K, Rb, Cs, and Fr (H is an exception, in spite it is in the first column it does not belong to the alkali metals family because it is a nonmetal). Other well known families are alkaline earth metals (column 2), halogens (column 3), and noble gases (column 18).

All the members of a family have the same number of valence electrons, i.e. electrons in the outermost shell.

  • <u>Nitrogen</u>, N, is in the column 15; it has 5 valence electrons, because its outer most shell has configurarion ns²np³ (n is 2 because nitrogen is in the second period).

The other members fo this family with the electron configuration of the outermost shell are:

  • <u>Phosphorus</u>, P, 3s² 3p³ (third period)

  • <u>Arsenic,</u> As, 4s² 4p³ (fourth period)

  • <u>Antimonium</u>, Sb, 5s² 5p³ (fith period)

  • <u>Bismuth</u>, Bi, 6s² 6p³ (sixth period)

  • <u>Moscovium</u>, Mc, 7s² 7p³ (seventh period)

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Let's consider the following thermochemical equation.

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We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

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ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol

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