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3 years ago

Nitrogen family - 5 valence electrons

Chemistry

1 answer:

Anna11 [10]3 years ago

6 0

Answer:

The elements that belong to the nitrogen family are nitrogen, phosphorus, arsenic, antimonium, bismuth, and moscovium.

Explanation:

Families are group of elements that belong to the same column in the periodic table.

Some families have a well known name. For instance, alkali metals is the family of the elements that belong to the first column: Li, Na, K, Rb, Cs, and Fr (H is an exception, in spite it is in the first column it does not belong to the alkali metals family because it is a nonmetal). Other well known families are alkaline earth metals (column 2), halogens (column 3), and noble gases (column 18).

All the members of a family have the same number of valence electrons, i.e. electrons in the outermost shell.

Nitrogen, N, is in the column 15; it has 5 valence electrons, because its outer most shell has configurarion ns²np³ (n is 2 because nitrogen is in the second period).

The other members fo this family with the electron configuration of the outermost shell are:

Phosphorus, P, 3s² 3p³ (third period)

Arsenic, As, 4s² 4p³ (fourth period)

Antimonium, Sb, 5s² 5p³ (fith period)

Bismuth, Bi, 6s² 6p³ (sixth period)

Moscovium, Mc, 7s² 7p³ (seventh period)

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Calculate the mass of nitrogen dissolved at room temperature in an 86.0 L home aquarium. Assume a total pressure of 1.0 atm and

Andrew [12]

Answer:

Mass of nitrogen gas dissolved= 1.1732 grams

Explanation:

According to Dalton's Law of partial pressure:

$P_{N_2}=P_{Total}X_{N_2}$

Where,

$P_{N_2}$ is the partial pressure of nitrogen

$P_{Total}$ is the Total pressure

$X_{N_2}$ is the mole fraction of nitrogen

Given :

Total pressure = 1.0 atm

Mole fraction of nitrogen = 0.78

Partial pressure of nitrogen:

$P_{N_2}=1.0\times 0.78 atm$

Partial pressure of nitrogen = 0.78 atm

According to Henry's law:

Solubility = Henry's constant (k)×Partial pressure

k = 6.26×10⁻⁴ mol/L-atm

Thus,

Solubility of nitrogen = 6.26×10⁻⁴ mol/L-atm×0.78 atm = 4.8828×10⁻⁴ mol/L

Given: Volume = 86.0 L

So, Moles of nitrogen gas dissolved:

Moles = Solubility (Concentration dissolved)×Volume

Moles = 4.8828×10⁻⁴ mol/L×86.0 L = 0.0419 moles

Also,

$moles=\frac{Mass(m)}{Molar\ mass (M)}$

$Mass\ of\ nitrogen=moles\times {Molar\ mass}$

Molar mass of nitrogen gas = 28 g/mol

So,

Mass of nitrogen gas dissolved = 0.0419 moles×28 g/mol = 1.1732 grams

6 0

4 years ago

a lead ball has a mass of 5.910 g and a diameter or 10.0 mm what is the density of lead in grams per cubic centimeters .The volu

storchak [24]

Answer:

11.3 g/cm³

Explanation:

Data Given:

Diameter of lead ball = 10.0 mm

Convert mm to cubic centimeter (cm³)

1 mm = 0.1 cm

So,

10.0 mm = 10.0 x 0.1 = 1 cm

mass of lead ball = 5.910 g

density of of lead ball =?

Solution:

To find density formula will be used

d = m/V ...........(1)

where

d = density

m = mass

V = volume

So,

To find the density of the lead ball (sphere), first we have to find volume of the ball.

To find volume of the ball following formula will be used

V = 4 . π . r³/ 3 ..............(2)

where

π = 3.14

r = radius

So,

r = D/2

D = 1 cm

So, radius will be

r = 1 cm / 2

r = 0.5 cm

Now put values in formula 2

V = (4)(3.14)(0.5cm)³/ 3

V = (12.56)(0.125 cm³) /3

V = 1.57 cm³/3

V = 0.523 cm³

So, the volume of the lead ball is 0.523 cm³

Now put values in equation 1

d = m/V

d = 5.910 g / 0.523 cm³

d = 11.3 g/cm³

Density of the lead ball = 11.3 g/cm³

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