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2 years ago

Nitrogen family - 5 valence electrons

Chemistry

1 answer:

Anna11 [10]2 years ago

6 0

Answer:

The elements that belong to the nitrogen family are nitrogen, phosphorus, arsenic, antimonium, bismuth, and moscovium.

Explanation:

Families are group of elements that belong to the same column in the periodic table.

Some families have a well known name. For instance, alkali metals is the family of the elements that belong to the first column: Li, Na, K, Rb, Cs, and Fr (H is an exception, in spite it is in the first column it does not belong to the alkali metals family because it is a nonmetal). Other well known families are alkaline earth metals (column 2), halogens (column 3), and noble gases (column 18).

All the members of a family have the same number of valence electrons, i.e. electrons in the outermost shell.

Nitrogen, N, is in the column 15; it has 5 valence electrons, because its outer most shell has configurarion ns²np³ (n is 2 because nitrogen is in the second period).

The other members fo this family with the electron configuration of the outermost shell are:

Phosphorus, P, 3s² 3p³ (third period)

Arsenic, As, 4s² 4p³ (fourth period)

Antimonium, Sb, 5s² 5p³ (fith period)

Bismuth, Bi, 6s² 6p³ (sixth period)

Moscovium, Mc, 7s² 7p³ (seventh period)

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How many atoms are in 5 grams of H2O?

mojhsa [17]

Hello!

We know that by the Law of Avogrado, for each mole of substance we have 6.02 * 10²³ atoms, if:

The molar mass of water (H2O)

H = 2 * (1u) = 2u

O = 1 * (16u) = 16u

---------------------------

The molar mass of H2O = 2 + 16 = 18 g / mol

If:

1 mol we have 6.02 * 10²³ atoms

1 mole of H2O we have 18 g

Then we have:

18 g ------------- 6.02 * 10²³ atoms

5 g -------------- x

$\dfrac{18}{5} = \dfrac{6.02*10^{23}}{x}$

$18*x = 5*6.02*10^{23}$

$18\:x = 3.01*10^{24}$

$x = \dfrac{3.01*10^{24}}{18}$

$\boxed{\boxed{x \approx 1.672*10^{23}\:atoms}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

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If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te

attashe74 [19]

Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
$pV=nRT$
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
$\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}$

If the supported load is W kg, then
$p_{1} = \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} = 20.3718W \, Pa$
Similarly,
$p_{2} = \frac{4W}{\pi d_{2}^{2}} \, Pa$

$\frac{p_{1}}{p_{2}} = \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}$

Because p₁/p₂ = T₁/T₂, therefore
$16d_{2}^{2} = \frac{293}{423} \\\\ d_{2}^{2} = \frac{0.6927}{16} \\\\ d_{2} = 0.2081 \, m$

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Answer: 20.8 cm diameter

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tresset_1 [31]

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Learn more about balance equation here:- brainly.com/question/11904811

#SPJ1

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