If a 22. 5 mm copper (ii) solution(solution a) had an absorbance of 1. 65. Then, the absorbance if 8 ml of solution a was used to prepare a 20. 0 ml of a new copper (ii) solution is 918.84.
According to Beer-Lambert law, the absorbance (A) of a substance depends on its concentration (c)
A = ε . l. c
where,
ε: absorptivity of the species
l: optical path length
A 22.5 mM phosphate solution (solution A) had an absorbance of 1.012.
A = ε . l . c
1.65 = ε . l . 22.5 mM
ε . l = 37.125 mM⁻¹
We will calculate the concentration of the second solution using the dilution rule.
C₁ . V₁ = C₂ . V₂
22.5mM . 8 mL = C₂ . 20.0 mL
C₂ = 24.75 mM
The absorbance of the second solution is:
A = (ε . l ). c
A = (37.125 mM⁻¹) x 24.75 mM = 918.84
Thus, we find that the value of absorbance is 918.84.
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Answer:
0.544 eV; Ag is a smaller atom.
Explanation:
1. Ionization energy of hydrogen
The outermost electrons in Rb and Ag are in 5s orbitals.
The formula for the energy of an electron in a hydrogen atom is
E = -13.6/n² eV
For a hydrogen atom in a 5s orbital,
E = -13.6/5² = -13.6/25 = -0.544 eV
The ionization energy would be 0.544 eV.
2. Rb vs Ag
The first electrons to be removed from Rb and Ag are in 5s orbitals.
The atomic radius of Ag is less than that of Rb because, as you go from left to right across the Row, you are adding 10 protons to the nucleus and 10 electrons to the outer shell.
The added electrons do not effectively shield each other from the attraction of the nucleus, so the 5s electron of Ag is closer in.
It takes more energy to remove the electron from silver, so the ionization energy of Ag is greater than that of Rb.
Answer:
salicylate ion
Explanation:
The spectroscopic analysis of aspirin will involve the complexing of iron(III) to the deprotonated form of salicylic acid (salicylate ion) to give a purple solution.