Y = x + 6
y = -3x + 6
put the system of linear equations into standard form
x - y = -6
-3x - y = -6
solution:
x = 0
y = 6
Answer:
(-2 ,3)
Step-by-step explanation:
Step 1: Rewrite first equation
x = 4 - 2y
-2x + y = 7
Step 2: Substitution
-2(4 - 2y) + y = 7
Step 3: Solve <em>y</em>
-8 + 4y + y = 7
-8 + 5y = 7
5y = 15
y = 3
Step 3: Plug in <em>y</em> to find <em>x</em>
x + 2(3) = 4
x + 6 = 4
x = -2
Answer:
(3, 0) and (5, 0)
Step-by-step explanation:
we have
we know that
The x-intercepts are the values of x when the value of y is equal to zero
so
For y=0
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
so
x=3, x=5
therefore
The x-intercepts are (3,0) and (5,0)
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
