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mafiozo [28]
3 years ago
15

Find the volume occupied by 18.0 g of helium gas at 29.0 ∘c and 1.33 atm of pressure.

Chemistry
1 answer:
otez555 [7]3 years ago
7 0
We can use the ideal gas law equation to find the volume occupied by the gas
PV = nRT
where 
P - pressure - 1.33 atm x 101 325 Pa/atm = 134 762 Pa
V - volume 
n - number of moles - 18.0 g / 4 g/mol = 4.5 mol 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 29 °C + 273 = 302 K
substituting these values in the equation 
134 762 Pa x V = 4.5 mol x 8.314 Jmol⁻¹K⁻¹ x 302 K 
V = 83.8 L
volume occupied by He is 83.8 L 
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Abundance of isotope (I) = 1.4% = 0.014

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Abundance of isotope (II) = 22.1 % = 0.221

Atomic mass of the Isotope (II) = number protons +  number of neutrons = 82 + 125 = 207 amu

Abundance of isotope (III) = 24.1% = 0.241

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Average atomic mass of an element =

\sum(\text{atomic mass of an isotopes}\times (\text{fractional abundance)})

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(204 amu\times 0.014+207 amu\times 0.221 amu+206\times 0.241+208 amu\times 0.524)=207.24 amu

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