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Leviafan [203]
3 years ago
11

A balloon contains helium gas expands from 230ml to 860 ml as more helium is added. What was the initial quantity of helium pres

ent if the expanded balloon contains 3.8x10^-4 mol, assuming constant temperature and pressure?
Chemistry
2 answers:
Kisachek [45]3 years ago
6 0

Answer:

n₁ = 1.0× 10⁻⁴ mol

Explanation:

Given data:

Initial volume of balloon = 230 mL

Initial number of moles of He =?

Final number of moles of He = 3.8 × 10⁻⁴ mol

Final volume of balloon = 860 mL

Solution:

The given problem will be solve through Avogadro law,

"Number of moles of gas and volume are directly proportional to each other at constant temperature and constant pressure"

Mathematical relationship:

V₁/n₁ = V₂/n₂

No we will put the values.

230 mL  /n₁   = 860 mL/ 3.8 × 10⁻⁴ mol

n₁ = 230 mL× 3.8 × 10⁻⁴ mol/ 860 mL

n₁ = 874 × 10⁻⁴ mol. mL / 860 mL

n₁ = 1.0× 10⁻⁴ mol

PolarNik [594]3 years ago
3 0

Answer: the answer is n1=n2v1/v2

Explanation:

hope this helped

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