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Leviafan [203]
2 years ago
11

A balloon contains helium gas expands from 230ml to 860 ml as more helium is added. What was the initial quantity of helium pres

ent if the expanded balloon contains 3.8x10^-4 mol, assuming constant temperature and pressure?
Chemistry
2 answers:
Kisachek [45]2 years ago
6 0

Answer:

n₁ = 1.0× 10⁻⁴ mol

Explanation:

Given data:

Initial volume of balloon = 230 mL

Initial number of moles of He =?

Final number of moles of He = 3.8 × 10⁻⁴ mol

Final volume of balloon = 860 mL

Solution:

The given problem will be solve through Avogadro law,

"Number of moles of gas and volume are directly proportional to each other at constant temperature and constant pressure"

Mathematical relationship:

V₁/n₁ = V₂/n₂

No we will put the values.

230 mL  /n₁   = 860 mL/ 3.8 × 10⁻⁴ mol

n₁ = 230 mL× 3.8 × 10⁻⁴ mol/ 860 mL

n₁ = 874 × 10⁻⁴ mol. mL / 860 mL

n₁ = 1.0× 10⁻⁴ mol

PolarNik [594]2 years ago
3 0

Answer: the answer is n1=n2v1/v2

Explanation:

hope this helped

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EXPLANATION: SO THE CORRECT ANSWER IS

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2 years ago
A ground state hydrogen atom absorbs a photon of light having a wavelength of 92.05 nm. It then gives off a photon having a wave
vodka [1.7K]
Absorbed photon energy
Ea = hc/λ.. (Planck's equation)
Ea = hc / 92.05^-9m 

<span>Energy emitted
Ee = hc/ 1736^-9m </span>

Energy retained ..
∆E = Ea - Ee = hc(1/92.05<span>^-9 - 1/1736^-9) </span>
<span>∆E = (6.625^-34)(3.0^8) (1.028^7)
∆E = 2.04^-18 J </span>

<span>Converting J to eV (1.60^-19 J/eV)
 ∆E = 2.04^-18 / 1.60^-19
∆E = 12.70 eV </span>

<span>Ground state (n=1) energy for Hydrogen = - 13.60eV </span>

<span>New energy state = (-13.60 + 12.70)eV = -0.85 eV </span>

<span>Energy states for Hydrogen
En = - (13.60 / n²) </span>

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4 0
2 years ago
What is the source of energy for the Sun?
nikitadnepr [17]

Answer:

Nuclear fusion

Explanation:

Nuclear fusion is the source of Sun's energy.. At the core where temperature and pressure are very high hydrogen atoms fuse into helium atom and release energy in the form of Gama rays.

3 0
3 years ago
Select the electron-domain geometry for a molecule with three bonding domains and one nonbonding domain.
mamaluj [8]

Answer: C) Tetrahedral

Explanation:

The number of electron pairs is 4 that means the hybridization will be sp^3 but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.

Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be sp^2.

Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be sp^3.

Trigonal bipyramidal geometry is possible when number of electron pairs is 5 and the hybridization will be sp^3d.

Octahedral geometry is possible when number of electron pairs is 6 and the hybridization will be sp^3d^2.

6 0
3 years ago
4. Describe the movement of the water molecules at cold temperatures.
kenny6666 [7]

Answer:

Point out to students that molecules of hot water are moving faster and are slightly further apart. The molecules of cold water are moving slower and are a little closer together. If students do not notice a difference, move the slider all the way to the left again and then quickly to the right.

2. How do molecules move in cold water?

Compare the speed of molecules in hot water compared to molecules in cold water? Water molecules move faster in hot water and slower in cold water. water molecules in cold, room temperature, and hot water. most of the liquid.

3 0
2 years ago
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