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lianna [129]
4 years ago
11

¿Cuál es el estado de oxidación del azufre en S203?

Chemistry
1 answer:
12345 [234]4 years ago
5 0

Answer:

+2

Explanation:

Stefan V. El oxígeno tendría un estado de oxidación de -2, por lo tanto el azufre tendría un estado de oxidación de +2

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Hey! need help with chem, multiple choice questions.
ladessa [460]
1. 6 carbon atoms and triple bonding between carbons 2 and 3
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7 0
3 years ago
How many atoms of Na are in 1.89 mol of Na?
atroni [7]

Answer:

1.138158E24 atoms or 1.14 x 10^24 atoms

Explanation:

To find atoms/particles from moles you just want to convert using avogadro's number which is 6.022 x 10^23

1.89 mol x 6.022 • 10^23

———— = 1.138158E24 atoms

1 mol

so 1.138158E24 atoms or 1.14 x 10^24 for scientific notation

hope this helps :)

5 0
2 years ago
There are several ways to express solution concentration: dilute, concentrated, ppm, molarity, molality, normality. All of these
Hoochie [10]

Answer:

just pick b

Explanation:

8 0
3 years ago
A sample of juice has a pH of 4.2. Whsat is the concentration in mol/dm3 of OH in the juice?<br>​
Annette [7]

Answer:

6 * 10^-4M

Explanation:

use this equation

[ H + ]  =  10  −  pH

6 0
3 years ago
2 A(g) + B(g) ---&gt; 2 C(g)Rate = k [A][B]At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The obse
Orlov [11]

Answer:

Lmol⁻¹s⁻¹

Explanation:

The rate law of the given reaction is:-

Rate=k[A][B]

Wherem, k is the rate constant.

Given that:-

Rate = 0.36 mol/Lsec = 0.36 M/sec

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Thus,

Applying in the equation as:-

0.36 M/sec =k × 3.0 M× 1.0 M

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<u>The units of k = Lmol⁻¹s⁻¹</u>

6 0
3 years ago
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