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lianna [129]
4 years ago
11

¿Cuál es el estado de oxidación del azufre en S203?

Chemistry
1 answer:
12345 [234]4 years ago
5 0

Answer:

+2

Explanation:

Stefan V. El oxígeno tendría un estado de oxidación de -2, por lo tanto el azufre tendría un estado de oxidación de +2

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_AlBr3+_K2SO4>_KBR+_Al2(SO4)3
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Balancing chemical equation means making a number of atoms or molecules equal on both sides. In other words, this means that the number of atoms and molecules of each reacting element needs to be the same as the number of atoms and molecules of those elements in the product.

Our reaction is:

AlBr3 + K2SO4 -> KBr + Al2(SO4)3

and we need to balance it.

Since there are 3 molecules of SO4 in the product we need to put 3 before the reactant K2SO4. There are also 2 atoms of Al in the product, so we need to put 2 in front AlBr3. Now we have 6 atoms of K and Br on the left side, so we need to put 6 in front of KBr in the product.

So, our balanced equation will look like this:

2AlBr3 + 3K2SO4 -> 6KBr + Al2(SO4)3

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3 years ago
A sample of helium has a volume of 3.49 L at 741 mmHg. What would be the volume if the pressure
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