Answer:
200 grams of NaOH are produced with the reaction of 5.00 moles of water
Explanation:
First of all you apply a rule of three to know the amount of moles of NaOH as follows: if 2 moles of water produce 2 moles of NaOH, 5 moles of water how many moles would they produce?

moles of NaOH= 5
Being:
- Na: 23 g/mole
- O: 16 g/mole
- H: 1 g/mole
the molar mass of NaOH is: 23 g/mole + 16 g/mole + 1 g/mole= 40 g/mole
Then a rule of three applies as follows: if in 1 mole there are 40 g of NaOH, in 5 moles how much mass is there?

mass= 200 g
<u><em>200 grams of NaOH are produced with the reaction of 5.00 moles of water</em></u>
Use cleaning products or soap it should help get the <span>pesticide out/off.
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To answer this question, you need to know the aluminum acetate weight and formula. Molecular weight of aluminum acetate is 204.11g/mol, so the concentration should be: (25.20/204.11 )/(0.185l) = 0.1234 mol/0.185l= 0.6673 M<span>
</span>The aluminum acetate Al(C2H3O2)3 which mean for one aluminum acetate there will be 3 acetate ion. The concentration of acetate should be: 0.6673 M= 2M
Answer:
The final balanced equation is :

Explanation:

Balancing in acidic medium:
First we will determine the oxidation and reduction reaction from the givne reaction :
Oxidation:

Balance the charge by adding 2 electrons on product side:
....[1]
Reduction :

Balance O by adding water on required side:

Now, balance H by adding
on the required side:

At last balance the charge by adding electrons on the side where positive charge is more:
..[2]
Adding [1] and [2]:

The final balanced equation is :
